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Revision History for A320142 (Underlined text is an addition; strikethrough text is a deletion.)

Showing entries 1-10 | older changes
A320142 Numbers that have exactly two middle divisors.
(history; published version)
#29 by Charles R Greathouse IV at Fri Aug 23 20:54:12 EDT 2024
STATUS

proposed

approved

#28 by Hartmut F. W. Hoft at Tue Aug 20 12:33:15 EDT 2024
STATUS

editing

proposed

#27 by Hartmut F. W. Hoft at Tue Aug 20 12:33:06 EDT 2024
COMMENTS

By the theorem in A067742 conjecture 2 is true. - Hartmut F. W. Hoft, Aug 18 2024

MATHEMATICA

a320142Q[k_] := Length[Select[Divisors[k], k/2<=#^2<2k&]]==2

a320142[n_] := Select[Range[n], a320142Q]

a320142[260] (* Hartmut F. W. Hoft, Aug 20 2024 *)

STATUS

approved

editing

#26 by N. J. A. Sloane at Fri Nov 09 20:25:07 EST 2018
STATUS

proposed

approved

#25 by Omar E. Pol at Mon Oct 08 22:00:33 EDT 2018
STATUS

editing

proposed

#24 by Omar E. Pol at Mon Oct 08 22:00:30 EDT 2018
EXAMPLE

.

#23 by Omar E. Pol at Mon Oct 08 22:00:10 EDT 2018
COMMENTS

Conjecture 1: numbers k with the property that the difference between the number symmetricof representationpartitions of sigma(k) has into an odd number of widthconsecutive 2parts onand the number of partitions of k into an even number of consecutive parts is equal mainto diagonal2.

Conjecture 2: numbers k with the property that the difference between the number ofsymmetric partitionsrepresentation of sigma(k into an odd number of) has consecutivewidth parts2 andon the number of partitions of k into an even number of consecutive parts is equal tomain 2diagonal.

EXAMPLE

On the other hand, in accordance with the first conjecture, 15 is in the sequence because there theare symmetricthree representationpartitions of sigma(15) = 24 into an odd number hasof widthconsecutive parts: [15], [8, 7], [5, 4, 3, 2, 1], and there is only one partition of 15 into an even onnumber theof mainconsecutive diagonalparts: [8, as7], therefore shownthe belowdifference inof the number of those partitions fourthis quadrant:3 - 1 = 2.

On the other hand, in accordance with the second conjecture, 15 is in the sequence because the symmetric representation of sigma(15) = 24 has width 2 on the main diagonal, as shown below in the fourth quadrant:

.

On the other hand, in accordance with the second conjecture, 15 is in the sequence because there are three partitions of 15 into an odd number of consecutive parts: [15], [8, 7], [5, 4, 3, 2, 1], and there is only one partition of 15 into an even number of consecutive parts: [8, 7], therefore the difference of the number of those partitions is 3 - 1 = 2.

STATUS

proposed

editing

#22 by Omar E. Pol at Mon Oct 08 21:20:56 EDT 2018
STATUS

editing

proposed

#21 by Omar E. Pol at Mon Oct 08 21:20:52 EDT 2018
EXAMPLE

On the other hand, in accordance with the second conjecture, 15 is in the sequence because there are three partitions of 15 into an odd number of consecutive parts: [15], [8, 7], [5, 4, 3, 2, 1], and there areis only one partition of 15 into an even number of consecutive parts: [8, 7], therefore the difference of the number of those partitions is 3 - 1 = 2.

STATUS

proposed

editing

#20 by Omar E. Pol at Sun Oct 07 19:33:00 EDT 2018
STATUS

editing

proposed

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Last modified August 29 11:24 EDT 2024. Contains 375516 sequences. (Running on oeis4.)