STATUS
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approved
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reviewed
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proposed
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proposed
def b(n, k):
if n == 0:
return 1
def b(n, k): return 1 if n==0 else sum([b(j, k) * b(n - j - 1, k) * k**j for j in range(n)])
print map([a, (n) for n in range(16)]) # Indranil Ghosh, Aug 10 2017
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print map(a, xrangerange(16)) # Indranil Ghosh, Aug 10 2017
def b(n, k): return 1 if n==0 else sum([b(j, k)*b(n - j - 1, k)*k**j for j in xrangerange(n)])
editing
approved
a(n) ~ n^(n*(n-1)/2). - Vaclav Kotesovec, Aug 19 2017
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a(n) = [x^n] 1/(1-x/(1-kn*x/(1-kn^2*x/(1-kn^3*x/(1-kn^4*x/(1- ... )))))).
approved
editing