STATUS
proposed
approved
proposed
approved
editing
proposed
From Seiichi Manyama, Aug 01 2019: (Start)
2^(5^0) + 5^(2^0) == 7 mod 10,
2^(5^1) + 5^(2^1) == 57 mod 10^2,
2^(5^2) + 5^(2^2) == 57 mod 10^3,
2^(5^3) + 5^(2^3) == 7057 mod 10^4. (End)
approved
editing
proposed
approved
editing
proposed
m str = (P(n) + Q(5, n)).to_s.reverse
m.to_s.reverse.split('').map(&:to_i)[0..n]
(0..n).map{|i| str[i].to_i}
approved
editing
proposed
approved
editing
proposed
Seiichi Manyama, <a href="/A290374/b290374.txt">Table of n, a(n) for n = 0..9999</a>
approved
editing