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Revision History for A288069 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Quotients obtained when the Zuckerman numbers are divided by the product of their digits.
(history; published version)
#32 by Harvey P. Dale at Mon Aug 16 15:51:49 EDT 2021
STATUS

editing

approved

#31 by Harvey P. Dale at Mon Aug 16 15:51:45 EDT 2021
MATHEMATICA

Select[Table[n/Max[Times@@IntegerDigits[n], Pi/100], {n, 5000}], IntegerQ] (* Harvey P. Dale, Aug 16 2021 *)

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approved

editing

#30 by Joerg Arndt at Thu Apr 01 09:44:16 EDT 2021
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reviewed

approved

#29 by Michel Marcus at Thu Apr 01 09:12:54 EDT 2021
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proposed

reviewed

#28 by Bernard Schott at Thu Apr 01 08:53:34 EDT 2021
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editing

proposed

#27 by Bernard Schott at Thu Apr 01 08:53:10 EDT 2021
CROSSREFS
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proposed

editing

Discussion
Thu Apr 01
08:53
Bernard Schott: … and 2 xrefs.
#26 by Bernard Schott at Thu Apr 01 08:51:40 EDT 2021
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editing

proposed

#25 by Bernard Schott at Thu Apr 01 08:50:58 EDT 2021
COMMENTS

Question: Is A067251 a subsequence? No, it appears in A056770 that not all integers other than multiples of 10 can be obtained as quotient, such as 15, 16, 24, 25, 26, 32, .... (see A342941).

STATUS

approved

editing

Discussion
Thu Apr 01
08:51
Bernard Schott: Just 'see A342941' in comment.
#24 by Charles R Greathouse IV at Mon Jun 05 23:53:32 EDT 2017
STATUS

editing

approved

#23 by Charles R Greathouse IV at Mon Jun 05 23:53:24 EDT 2017
COMMENTS

The limit of the sequence is infinite: for any x, there is some N such that, for all n > N, a(n) > x. Proof: a Zuckerman number with d digits is at least 10^(d-1) and has a digit product at most 9^d and so has a quotient at least 10^(d-1)/9^d which goes to infinity with d. - Charles R Greathouse IV, Jun 05 2017

STATUS

proposed

editing