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<a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (4,-6,4,-1).
a(x-1n) = 16*(xn+1)^3) - 28*(xn+1)^2) + 16*x(n+1) - 3 for xn>0.
From G. C. Greubel, Dec 25 2016: (Start)
G.f.: (1 + 41*x + 51*x^2 + 3*x^3)/(1 - x)^4.
E.g.f.: (1 + 44*x + 68*x^2 + 16*x^3)*exp(x).
a(n) = 4*a(n-1) - 6*a(n-2) + 4*a(n-3) - a(n-4). (End)
Table[16*(n+1)^3 - 28*(n+1)^2 + 16*(n+1) - 3, {n, 0, 50}] (* or *) LinearRecurrence[{4, -6, 4, -1}, {1, 45, 225, 637}, 50] (* G. C. Greubel, Dec 25 2016 *)
(PARI) for(n=0, 50, print1(16*(n+1)^3 - 28*(n+1)^2 + 16*(n+1) - 3, ", ")) \\ G. C. Greubel, Dec 25 2016
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for i in range(0, 2011001):
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Indranil Ghosh, <a href="/A280059/b280059.txt">Table of n, a(n) for n = 0..1000</a>
a(x-1)=16*(x^3)-28*(x^2)+16*x-3 for x>0.
allocated for Indranil GhoshNumber of 2 X 2 matrices having all elements in {-n,..,0,..,n} with determinant = permanent.
1, 45, 225, 637, 1377, 2541, 4225, 6525, 9537, 13357, 18081, 23805, 30625, 38637, 47937, 58621, 70785, 84525, 99937, 117117, 136161, 157165, 180225, 205437, 232897, 262701, 294945, 329725, 367137, 407277, 450241, 496125
0,2
a(x-1)=16*(x^3)-28*(x^2)+16*x-3.
def t(n):
s=0
for a in range(-n, n+1):
for b in range(-n, n+1):
for c in range(-n, n+1):
for d in range(-n, n+1):
if (a*d-b*c)==(a*d+b*c):
s+=1
return s
for i in range(0, 201):
print str(i)+" "+str(t(i))
Cf. A210000.
allocated
nonn
Indranil Ghosh, Dec 25 2016
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