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b(n) = n*lnlog((n+1)*lnlog((n+2)*lnlog(...))) ~ n*lnlog(n). - Andrey Zabolotskiy, Dec 01 2016
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b(n) = n*ln((n+1)*ln((n+2)*ln(...))) ~ n*ln(n). - Andrey Zabolotskiy, Dec 01 2016
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In this case b(1) = 1.3679012617... A278812. If b(1) were chosen smaller the sequence would approach 1, if it were chosen greater the sequence would at some point violate b(n-1)b(n+1)/b(n)^2 < 1 and from there on quickly escalate.
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