Revision History for A268524
(Underlined text is an addition;
strikethrough text is a deletion.)
Showing entries 1-10
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#22 by Michael De Vlieger at Sat Jun 25 17:07:08 EDT 2022
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#21 by Jon E. Schoenfield at Sat Jun 25 16:00:01 EDT 2022
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#20 by Jon E. Schoenfield at Sat Jun 25 15:59:58 EDT 2022
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Start with A = [[[1]]], iteratively replace every element Aijk with Aijk * [[[1, 1], [1, 0]], [[1, 0], [0, 0]]]. a(n) is the sum of the resulting array inside of the cubic region i, j, k < n. - Peter Karpov, Mar 01 2016
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approved
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#19 by N. J. A. Sloane at Thu Mar 24 12:15:35 EDT 2016
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#18 by N. J. A. Sloane at Thu Mar 24 12:14:27 EDT 2016
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Number of tripletstriples 0 <= i, j, k < n such that bitwise AND of all pairs (i, j), (j, k), (k, i) is 0. - Peter Karpov, Mar 01 2016
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Discussion
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| Thu Mar 24
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| N. J. A. Sloane: "Triples" is correct. NOT "triplets" (unless you are a midwife)
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#17 by Michel Marcus at Thu Mar 24 12:00:08 EDT 2016
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#16 by Michel Marcus at Thu Mar 24 11:59:58 EDT 2016
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Start with A = [[[1]]], iteratively replace every element Aijk with Aijk * [[[1, 1], [1, 0]], [[1, 0], [0, 0]]]. a(n) is the sum of the resulting array inside of the cubic region i, j, k < n. - Peter Karpov, Mar 01 2016
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(PARI) a(n) = if (n==1, 1, 3*a(ceil(n/2)) + a(floor(n/2))); \\ Michel Marcus, Mar 24 2016
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#15 by Peter Karpov at Tue Mar 01 13:42:36 EST 2016
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#14 by Peter Karpov at Tue Mar 01 12:25:24 EST 2016
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Start with A = [[[1]]], iteratively replace every element AijAijk with AijAijk * [[[1, 1], [1, 0]], [[1, 0], [0, 0]]]. a(n) is the sum of the resulting array inside of the cubic region i, j, k < n. - Peter Karpov, Mar 01 2016
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#13 by Peter Karpov at Tue Mar 01 12:17:53 EST 2016
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