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Revision History for A265042 (Underlined text is an addition; strikethrough text is a deletion.)

Showing entries 1-10 | older changes
A265042 a(n) = the unique number k such that T(p + n) == k mod p for all primes p, where T(n) = A000798(n) = number of topologies on n points.
(history; published version)
#43 by Alois P. Heinz at Sat Jun 15 11:41:49 EDT 2024
STATUS

proposed

approved

#42 by Michel Marcus at Sat Jun 15 11:39:48 EDT 2024
STATUS

editing

proposed

#41 by Michel Marcus at Sat Jun 15 11:39:42 EDT 2024
COMMENTS

In conclusion, a(5) is a number of the form 2*3*5*7*11*13*n - 2767, that is, 30030*n - 2767. Moreover we know that 209527 < a(5) < 419054. So a(5) is the one of these numbers: 237473, 267503, 297533, 327563, 357593, 387623, 417653. If we take into consideration the first four inequalities, which are 4 < 7 < 8, 29 < 51 < 58, 355 < 634 < 710, 6942 < 12623 < 13884, then 387623 seems a strong candidate for a(5) because of relevant proportions in inequalities.

STATUS

approved

editing

#40 by Charles R Greathouse IV at Mon Apr 11 14:59:27 EDT 2016
STATUS

editing

approved

#39 by Charles R Greathouse IV at Mon Apr 11 14:59:24 EDT 2016
FORMULA

A000798(n+1) < a(n) < 2*A000798(n+1), for n > 0. - Altug Alkan, Dec 17 20162015

STATUS

approved

editing

#38 by N. J. A. Sloane at Sun Dec 20 11:13:26 EST 2015
STATUS

editing

approved

#37 by N. J. A. Sloane at Sun Dec 20 11:13:17 EST 2015
COMMENTS

Due toFrom the inequality which is given in the formula section, since A000798(6) = 209527, we have 209527 < a(5) < 419054. The same inequality shows that a(17) has 36 digits (A000798 is currently known only for n <= 18).

If we want to analyseanalyze more deeply,

In conclusion, a(5) is thea number of the form 2*3*5*7*11*13*n - 2767, that is , 30030*n - 2767. Moreover we know that 209527 < a(5) < 419054. So a(5) is the one of these numbers : : 237473, 267503, 297533, 327563, 357593, 387623, 417653. And this trying to computing of a(5) also explains the reason of the fact that there is no a(5) in sequence, currently. At this point, ifIf we take into consideration the first four inequalities , which are 4 < 7 < 8, 29 < 51 < 58, 355 < 634 < 710, 6942 < 12623 < 13884, then 387623 seems a strong candidate for a(5) because of relevant proportions in inequalities.

STATUS

proposed

editing

Discussion
Sun Dec 20 11:13
N. J. A. Sloane: Edited
#36 by Altug Alkan at Sun Dec 20 09:59:17 EST 2015
STATUS

editing

proposed

#35 by Altug Alkan at Sun Dec 20 09:58:08 EST 2015
COMMENTS

In conclusion, a(5) is the number of the form 2*3*5*7*11*13*n - 2767, that is 30030*n - 2767. Moreover we know that 209527 < a(5) < 419054. So a(5) is the one of these numbers : 237473, 267503, 297533, 327563, 357593, 387623, 417653. And this trying to computing of a(5) also explains the reason of the fact that there is no a(5) in sequence, currently. At this point, if we take into consideration first four inequalities which are 4 < 7 < 8, 29 < 51 < 58, 355 < 634 < 710, 6942 < 12623 < 13884, 387623 seems a strong candidate for a(5) because of relevant proportions in inequalities.

#34 by Altug Alkan at Sun Dec 20 09:55:50 EST 2015
COMMENTS

In conclusion, a(5) is the number of the form 2*3*5*7*11*13*n - 2767, that is 30030*n - 2767. Moreover we know that 209527 < a(5) < 419054. So a(5) is the one of these numbers : 237473, 267503, 297533, 327563, 357593, 387623, 417653. And this trying to computing of a(5) also explains the reason of the fact that there is no a(5) in sequence, currently. At this point, if we take into consideration first four inequalities which are 4 < 7 < 8, 29 < 51 < 58, 355 < 634 < 710, 6942 < 12623 < 13884, 387623 seems a strong candidate for a(5) because of relevant proportions.

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Last modified August 29 06:09 EDT 2024. Contains 375510 sequences. (Running on oeis4.)