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nonn,tabf,walk,changed,less
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The sum of the antidiagonals of each triangle in each slice gives A261357. -_ _Dimitri Boscainos_, Aug 21 2015
T(i+1,j,k,l) = 2*T(i,j-1,k-1,l-1) + T(i,j-1,k-1,l) + T(i,j-1,k,l) + T(i,j,k,l); a(i,j,k,-1)=0,...; a(0,0,0,0)=1.
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T(i+1,j,k,l) = 2*T(i,j-1,k-1,l-1)+T(i,j-1,k-1,l)+T(i,j-1,k,l)+T(i,j,k,l); a(i,j,k,-1)=0,...; a(0,0,0,0)=1.
T(n,i,j,k) = 2^k*binomial(n,i)*binomial(i,j)*binomial(j,k). - Dimitri Boscainos, Aug 21 2015
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