proposed
approved
proposed
approved
editing
proposed
Let s be a palindrome and put a(1) = s. Let a(2) be the least palindromic prime having s in the middle; for n > 2, let a(n) be the least palindromic prime having a(n-1) in the middle. Then (a(n)) is the sequence of minimal nested palindromic primes with seed s. (For A260250, the seed is not an integer, so that the offset is 2.)
proposed
editing
editing
proposed
nonn,base,easy,changed
proposed
editing
editing
proposed
Let s be a palindrome and put a(1) = s. Let a(2) be the least palindromic prime having s in the middle; for n > 2, let a(n) be the least palindromic prime have having a(n-1) in the middle. Then (a(n)) is the sequence of minimal nested palindromic primes with seed s. (For A260250, the seed is not an integer, so that the offset is 2.)
proposed
editing
editing
proposed
allocated for Clark KimberlingMinimal nested palindromic primes with seed 000000000.
1300000000031, 713000000000317, 1471300000000031741, 12147130000000003174121, 3121471300000000031741213, 1213121471300000000031741213121, 33121312147130000000003174121312133, 323312131214713000000000317412131213323
2,1
Let s be a palindrome and put a(1) = s. Let a(2) be the least palindromic prime having s in the middle; for n > 2, let a(n) be the least palindromic prime have a(n-1) in the middle. Then (a(n)) is the sequence of minimal nested palindromic primes with seed s. (For A260250, the seed is not an integer, so that the offset is 2.)
Clark Kimberling, <a href="/A260250/b260250.txt">Table of n, a(n) for n = 2..200</a>
As a triangle:
000000000
1300000000031
713000000000317
1471300000000031741
12147130000000003174121,
3121471300000000031741213
1213121471300000000031741213121,
s0 = "000000000"; s = {ToExpression[s0]}; Do[NestWhile[# + 1 &, 1, ! PrimeQ[tmp = FromDigits[Join[#, IntegerDigits[Last[s], 10, Max[StringLength[s0], Length[IntegerDigits[Last[s]]]]], Reverse[#]]&[IntegerDigits[#]]]] &]; AppendTo[s, tmp], {10}]; s0 <> ", " <> StringTake[ToString[Rest[s]], {2, -2}]
(* Peter J. C. Moses, Sep 23 2015 *)
Cf. A261881.
allocated
nonn,easy
Clark Kimberling, Sep 24 2015
approved
editing
allocated for Clark Kimberling
allocated
approved