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Number of length n+2 0..3 arrays with every three consecutive terms having the sum of some two elements equal to twice the third.
Column 3 of A248433
Empirical: a(n) = a(n-1) + 2*a(n-3) - 2*a(n-4).
Empirical g.f.: 4*x*(4 + x + x^2 - 7*x^3) / ((1 - x)*(1 - 2*x^3)). - Colin Barker, Nov 08 2018
Some solutions for n=6:
Column 3 of A248433.
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R. H. Hardin, <a href="/A248428/b248428.txt">Table of n, a(n) for n = 1..210</a>
allocated for R. H. Hardin
Number of length n+2 0..3 arrays with every three consecutive terms having the sum of some two elements equal to twice the third
16, 20, 24, 28, 36, 44, 52, 68, 84, 100, 132, 164, 196, 260, 324, 388, 516, 644, 772, 1028, 1284, 1540, 2052, 2564, 3076, 4100, 5124, 6148, 8196, 10244, 12292, 16388, 20484, 24580, 32772, 40964, 49156, 65540, 81924, 98308, 131076, 163844, 196612, 262148
1,1
Column 3 of A248433
Empirical: a(n) = a(n-1) +2*a(n-3) -2*a(n-4)
Some solutions for n=6
..1....1....1....2....2....0....1....1....2....3....2....1....1....0....0....3
..0....3....2....1....0....1....0....3....0....2....0....3....1....1....0....1
..2....2....3....3....1....2....2....2....1....1....1....2....1....2....0....2
..1....1....1....2....2....3....1....1....2....3....2....1....1....0....0....0
..0....0....2....1....0....1....3....0....0....2....3....3....1....1....0....1
..2....2....3....0....1....2....2....2....1....1....1....2....1....2....0....2
..1....1....1....2....2....3....1....1....2....0....2....1....1....3....0....3
..0....0....2....1....3....1....3....3....0....2....3....0....1....1....0....1
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R. H. Hardin, Oct 06 2014
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