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a(n) = 2*floor((n-1)^2/4) + 3*ceiling(n^2/2) (conjectured). _- _Ralf Stephan_, Jan 13 2014
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a(n)*Pi is the total length of irregular spiral (center points: 1, 2, 3, 4) after n- rotations.
Let point points 1, 2, 3 & 4 be placed on a straight line at interval intervals of 1 unit. At point 1 make a half unit circle then at point 2 make another half circle and maintain continuity of circumferences. Continue using this procedure at point 3, 4, 1, ... and so on. The form is expanded spiral. See illustration in links.
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Conjecture: a(n) = 1-(-1)^n-n+2*n^2. a(n) = 2*a(n-1)-2*a(n-3)+a(n-4). G.f.: -x*(5*x^2+3)/((x-1)^3*(x+1)). - Colin Barker, Jan 16 2014
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