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Number of Mersenne primes that have between 10^n and 10^(n+1) - 1 digits.
(history; published version)
#22 by N. J. A. Sloane at Sat Nov 02 22:02:44 EDT 2013
STATUS

proposed

approved

#21 by Jon E. Schoenfield at Sat Nov 02 16:56:38 EDT 2013
STATUS

editing

proposed

#20 by Jon E. Schoenfield at Sat Nov 02 16:56:36 EDT 2013
COMMENTS

If this sequence were to actually be stable, this would mean that the number of Mersenne primes having between 10^n and 10^(n+1) - 1 digits is always around 6, when the number of prime numbers in the same digit number group constantly increases : around 2.3*10^(10^(n+1)-(n+1)). Also the number of Mersenne numbers in the same digit group constantly increases (though much less than the number of prime numbers) : 9*10^n/[(n+1)*lnlog(2) + lnlog(lnlog(10)/lnlog(2))*lnlog(2)/lnlog(10)]. So, if a(n) is really rather stable (around 6), Mersenne primes frequency among Mersenne numbers lower than x is converging towards 0 in the magnitude of [lnlog(lnlog(x))]^2/lnlog(x). Hence primes are still around 6*[lnlog(lnlog(x))]^2 more frequent among Mersenne numbers than among numbers.

STATUS

approved

editing

#19 by T. D. Noe at Sat Jul 20 14:48:53 EDT 2013
STATUS

editing

approved

#18 by T. D. Noe at Sat Jul 20 14:48:46 EDT 2013
KEYWORD

nonn,hard,changed,base

STATUS

proposed

editing

#17 by T. D. Noe at Fri Jul 19 12:35:26 EDT 2013
STATUS

editing

proposed

#16 by T. D. Noe at Fri Jul 19 12:34:59 EDT 2013
COMMENTS

At the moment (Jul 18 July 2013), there are already 4 Mersenne primes in the next group (n = 7), the last one was discovered on Jan 25 January 2013 and has 17,425,170 17425170 digits.

Note that for n = 6, a(n) = 7 still needs full confirmation, as tests for all factors between M42 = M_25,964,951 25964951 and M_44,457,869 44457869 (more than 10^7 digits) have only made once and a double check is needed to confirm a(6) = 7.

#15 by T. D. Noe at Fri Jul 19 12:32:51 EDT 2013
NAME

Number of Mersenne primes that have between 10^n and 10^(n+1) - 1 digits, starting n = 0.

LINKS

Wikipedia, <a href="http://en.wikipedia.org/wiki/Great_Internet_Mersenne_Prime_Search">Great Internet Mersenne Prime Search</a> or more up to date the French version: <a href="http://fr.wikipedia.org/wiki/Great_Internet_Mersenne_Prime_Search">Great Internet Mersenne Prime Search (FR)</a>

Wikipedia, <a href="http://en.wikipedia.org/wiki/Great_Internet_Mersenne_Prime_Search">Great Internet Mersenne Prime Search</a> or more up to date the French version: <a href="http://fr.wikipedia.org/wiki/Great_Internet_Mersenne_Prime_Search">Great Internet Mersenne Prime Search (FR)</a>

EXAMPLE

* M8 = M_31 = 2147483647,

* M9 = M_61 = 2305843009213693951,

* M10 = M_89 = 618970019642690137449562111,

* M11 = M_107 = 162259276829213363391578010288127,

* M12 = M_127 = 170141183460469231731687303715884105727.

CROSSREFS
KEYWORD

nonn,nice,hard,changed

STATUS

proposed

editing

#14 by Olivier de Mouzon at Fri Jul 19 09:03:46 EDT 2013
STATUS

editing

proposed

#13 by Olivier de Mouzon at Fri Jul 19 09:03:28 EDT 2013
COMMENTS

If this sequence were to actually be stable, this would mean that the number of Mersenne primes having between 10^n and 10^(n+1) - 1 digits is always around 6, when the number of prime numbers in the same digit number group constantly increases : around 2.3*10^(10^(n+1)-(n+1)). Also the number of Mersenne numbers in the same digit group constantly increases (though much less than the number of prime numbers) : 9*10^n/[(n+1)*ln(2) + ln(ln(10)/ln(2))*ln(2)/ln(10)]. So, if a(n) is really rather stable (around 6), Mersenne primes frequency among Mersenne numbers lower than x is converging towards 0 in the magnitude of [ln(ln(x))]^2/ln(x). Hence primes are still around 6*[ln(ln(x))]^2 more frequent among Mersenne numbers than among numbers.

STATUS

proposed

editing