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#[[3]]-#[[1]]&/@Partition[Range[0, 20]!, 3, 1] (* Harvey P. Dale, Aug 10 2023 *)
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For n >= 3, a(n) = number whose factorial base representation (A007623) begins with digits {n-1} and {n-2} followed by n-3 zeros. Viewed in that base, this sequence looks like this: 1, 21, 320, 4300, 54000, 650000, 7600000, 87000000, 980000000, A900000000, BA000000000, ... (where "digits" A and B stand for placeholder values 10 and 11 respectively). - Antti Karttunen, May 07 2015.
The Formula Described for the sequence is expressed by a(n) = n! - (n-2)!. The values for the same if, n = 2 the term thus obtained is 1. Also for values of n as 3 and 4 the terms are 5 and 22 respectively. But the terms respective terms seen in the series occupies term number 0, 1 and 2 (if count from 0) or term number 1, 2 and 3 (if taken from 1). The value of n taken in the formula gives terms which are of preceding or succeeding term numbers.
So, according to my observation in sequence of Factorials and refereed sequences A000142, A001563 the formula according to me can be a(n) = (n+2)!-n!.
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The Formula Described for the sequence is expressed by a(n) = n! - (n-2)!. The values for the same if, n = 2 the term thus obtained is 1. Also for values of n as 3 and 4 the terms are 5 and 22 respectively. But the terms respective terms seen in the series occupies term number 0, 1 and 2 (if count from 0) or term number 1, 2 and 3 (if taken from 1). The value of n taken in the formula gives terms which are of preceding or succeeding term numbers.
So, according to my observation in sequence of Factorials and refereed sequences AOOO142, A001563 the formula according to me can be a(n) = (n+2)!-n!.
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