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Number of (n+1)X3 X 3 0..2 arrays with the number of clockwise edge increases in every 2X2 2 X 2 subblock equal to two.
Column 2 of A205836.
Empirical: a(n) = 7*a(n-1) -8*a(n-2) +6*a(n-3) for n>4.
Empirical g.f.: 3*x*(37 - 49*x + 40*x^2 + 2*x^3) / (1 - 7*x + 8*x^2 - 6*x^3). - Colin Barker, Jun 13 2018
Some solutions for n=4:
Cf. A205836.
R. H. Hardin , Feb 01 2012
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_R. H. Hardin (rhhardin(AT)att.net) _ Feb 01 2012
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R. H. Hardin, <a href="/A205830/b205830.txt">Table of n, a(n) for n = 1..210</a>
allocated for Ron HardinNumber of (n+1)X3 0..2 arrays with the number of clockwise edge increases in every 2X2 subblock equal to two
111, 630, 3642, 21126, 122526, 710526, 4120230, 23892558, 138549222, 803425470, 4658939862, 27016470606, 156664328166, 908472171486, 5268089398710, 30548834388078, 177147958555782, 1027253571178110, 5956884336128982
1,1
Column 2 of A205836
Empirical: a(n) = 7*a(n-1) -8*a(n-2) +6*a(n-3) for n>4
Some solutions for n=4
..0..1..1....1..2..0....2..1..1....0..0..1....2..1..0....2..1..1....0..2..1
..2..0..2....1..0..1....1..0..2....2..1..2....0..2..1....1..0..2....2..1..2
..2..1..0....2..1..0....2..1..0....0..2..0....1..0..2....2..1..0....0..2..0
..1..0..1....0..2..1....0..2..1....2..1..2....2..1..0....0..2..1....2..0..2
..0..1..2....2..1..2....1..0..2....1..2..1....0..2..1....2..0..2....0..1..0
allocated
nonn
R. H. Hardin (rhhardin(AT)att.net) Feb 01 2012
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allocated for Ron Hardin
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