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Revision History for A178248 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
a(n) = 12^n + 1.
(history; published version)
#38 by Michel Marcus at Sun Dec 17 02:36:44 EST 2023
STATUS

reviewed

approved

#37 by Stefano Spezia at Sun Dec 17 01:55:32 EST 2023
STATUS

proposed

reviewed

#36 by Elmo R. Oliveira at Sat Dec 16 18:50:33 EST 2023
STATUS

editing

proposed

Discussion
Sun Dec 17
01:55
Stefano Spezia: Thanks
#35 by Elmo R. Oliveira at Sat Dec 16 18:49:54 EST 2023
FORMULA

GO.g.f.: (2-13*x)/(1-13*x+12*x^2) = (2-13*x)/((1-x)(1-12*x)).

STATUS

proposed

editing

#34 by Michel Marcus at Sat Dec 16 03:25:55 EST 2023
STATUS

editing

proposed

Discussion
Sat Dec 16
14:29
Stefano Spezia: I do not understand why you changed o.g.f. with g.f. … o.g.f. was fine too
18:49
Elmo R. Oliveira: Stefano, my intention was just to leave the term g.f. OEIS standard in this sequence. If you understand that in this case it is unnecessary, return to o.g.f, ok.
#33 by Michel Marcus at Sat Dec 16 03:23:35 EST 2023
FORMULA

a(n) = (1/12)*(11*A016125(n) + 13)/12. (End)

STATUS

proposed

editing

#32 by Elmo R. Oliveira at Fri Dec 15 17:24:10 EST 2023
STATUS

editing

proposed

#31 by Elmo R. Oliveira at Fri Dec 15 17:23:36 EST 2023
FORMULA

O.gG.f.: (2-13*x)/(1-13*x+12*x^2) = (2-13*x)/((1-x)(1-12*x)).

STATUS

proposed

editing

#30 by Elmo R. Oliveira at Fri Dec 15 10:41:55 EST 2023
STATUS

editing

proposed

#29 by Elmo R. Oliveira at Fri Dec 15 10:35:24 EST 2023
FORMULA

O.g.f.: (2 - 13 *x)/(1 - 13 *x + 12 *x^2) = (2 - 13 *x)/((1 - x)(1 - 12 *x)).

From Elmo R. Oliveira, Dec 15 2023: (Start)

a(n) = 12*a(n-1) - 11 for n>0.

a(n) = 13*a(n-1) - 12*a(n-2) for n>1.

a(n) = A001021(n)+1 = A024140(n)+2.

a(n) = (1/12)*(11*A016125(n) + 13). (End)

STATUS

approved

editing