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Revision History for A169827 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Multiples of 840.
(history; published version)
#14 by Charles R Greathouse IV at Tue Apr 16 09:50:21 EDT 2024
STATUS

editing

approved

#13 by Charles R Greathouse IV at Tue Apr 16 09:50:17 EDT 2024
PROG

(PARI) a(n)=840*n \\ Charles R Greathouse IV, Apr 16 2024

STATUS

proposed

editing

#12 by Elmo R. Oliveira at Tue Apr 16 09:45:30 EDT 2024
STATUS

editing

proposed

#11 by Elmo R. Oliveira at Tue Apr 16 09:45:07 EDT 2024
#10 by Elmo R. Oliveira at Tue Apr 16 09:38:15 EDT 2024
STATUS

proposed

editing

Discussion
Tue Apr 16
09:40
Elmo R. Oliveira: It's okay. Thanks.
#9 by David A. Corneth at Tue Apr 16 09:15:43 EDT 2024
STATUS

editing

proposed

#8 by David A. Corneth at Tue Apr 16 09:15:07 EDT 2024
FORMULA

a(n) = 2*A169825(n) = 14*A169823(n) = 21*A317095(n) = 28*A249674(n) = 30*A135628(n) = 40*A008603(n) = 60*A008596(n) = 420*A005843(n) = 840*A001477(n). (End)

STATUS

proposed

editing

Discussion
Tue Apr 16
09:15
David A. Corneth: Hope attribution to you is okay
#7 by Elmo R. Oliveira at Tue Apr 16 08:25:45 EDT 2024
STATUS

editing

proposed

#6 by Elmo R. Oliveira at Tue Apr 16 08:17:32 EDT 2024
LINKS

<a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (2,-1).

FORMULA

From Elmo R. Oliveira, Apr 16 2024: (Start)

G.f.: 840*x/(x-1)^2.

E.g.f.: 840*x*exp(x).

a(n) = 840*n = 2*a(n-1) - a(n-2) for n >= 2.

a(n) = 2*A169825(n) = 14*A169823(n) = 21*A317095(n) = 28*A249674(n) = 30*A135628(n) = 40*A008603(n) = 60*A008596(n) = 420*A005843(n). (End)

KEYWORD

nonn,easy

STATUS

approved

editing

#5 by N. J. A. Sloane at Thu Aug 13 14:02:28 EDT 2020
LINKS

Erich Friedman, <a href="httphttps://www2erich-friedman.stetsongithub.edu/~efriedmaio/numbers.html">What's Special About This Number?</a>

Discussion
Thu Aug 13
14:02
OEIS Server: https://oeis.org/edit/global/2866