proposed

approved

editing

proposed

The fifth row of the ED2 array A167560.

G. C. Greubel, <a href="/A167562/b167562.txt">Table of n, a(n) for n = 1..1000</a>

<a href="/index/Rec#order_05">Index entries for linear recurrences with constant coefficients</a>, signature (5,-10,10,-5,1).

a(n) = 5*n^4 + 10*n^3 + 67*n^2 + 14*n + 24.

GF(z) = G.f.: (24*z^4 - 48*z^3 + 144*z^2 - 120*z + 120)/(1-z)^5.

a(n) = 5*a(n-1) - 10*a(n-2) + 10*a(n-3) - 5*a(n-4) + a(n-5). - G. C. Greubel, Jun 16 2016

Table[5*n^4 + 10*n^3 + 67*n^2 + 14*n + 24, {n, 1, 100}] (* or *) LinearRecurrence[{5, -10, 10, -5, 1}, {120, 480, 1344, 3072, 6144}, 100] (* G. C. Greubel, Jun 16 2016 *)

approved

editing

_Johannes W. Meijer (meijgia(AT)hotmail.com), _, Nov 10 2009

The fifth row of the ED2 array A167560

120, 480, 1344, 3072, 6144, 11160, 18840, 30024, 45672, 66864, 94800, 130800, 176304, 232872, 302184, 386040, 486360, 605184, 744672, 907104, 1094880, 1310520, 1556664, 1836072, 2151624, 2506320, 2903280, 3345744, 3837072

1,1

a(n) = 5*n^4+10*n^3+67*n^2+14*n+24

GF(z) = (24*z^4-48*z^3+144*z^2-120*z+120)/(1-z)^5

Equals the fifth row of the ED2 array A167560.

easy,nonn

Johannes W. Meijer (meijgia(AT)hotmail.com), Nov 10 2009

approved