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Module[{nn = 30, t1, t2}, t1 = FromDigits/@Select[Table[PadRight[{2}, n, 3], {n, 2, nn}], PrimeQ[Total[#]] &]; t2 = FromDigits/@ Select[ Table[ PadRight[{2, 2}, n, 3], {n, 2, nn}], PrimeQ[Total[#]] &]; Union[ Join[ {2, 3}, t1, t2]]] (* Harvey P. Dale, Mar 06 2013 *)
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The number of twos is 3 - A039701(n) if n > 1. - Curtz
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The number of twos is 3 - A039701(n) if n > 1. - Curtz
If prime(n) is congruent to 1 mod 6, then a(n) starts with 22, but if prime(n) is congruent to 5 mod 6, then a(n) starts with 2. - Alonso del Arte, Dec 04 2013
We search for w twos and t threes in prime(n) = 2*w + 3*t. If t = floor(prime(n)/3) would lead to w = 1/2, we decrease t by 1.
The number of twos is 3 - A039701(n) if n > 1.
a(3) = 23 because the third prime is 5 and 2 + 3 = 5.
a(4) = 223 because the fourth prime is 7 and 2 + 2 + 3 = 7.
a(5) = 2333 because the fifth prime is 11 and 2 + 3 + 3 + 3 = 11.
Module[{nn = 30, t1, t2}, t1 = FromDigits/@Select[Table[PadRight[{2}, n, 3], {n, 2, nn}], PrimeQ[Total[#]] &]; t2 = FromDigits/@Select[Table[ PadRight[ {2, 2}, n, 3], {n, 2, nn}], PrimeQ[Total[#]] &]; Union[Join[{2, 3}, t1, t2]]] (* Harvey P. Dale, Mar 06 2013 *)
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a(0)=2, a(1)=3. Then 2 or 22 followed by a string of 3's such than that the sum of the digits of a(n) is equal to prime(n).
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