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a(n) = 4*a(n-1) - 3*a(n-2) + 2*a(n-3) - 1*a(n-4).
(history; published version)
#3 by Russ Cox at Fri Mar 30 17:39:33 EDT 2012
FORMULA

O.g.f.: -x(-1+3x+x^3)/(1-4x+3x^2-2x^3+x^4). - _R. J. Mathar (mathar(AT)strw.leidenuniv.nl), _, Apr 03 2008

EXTENSIONS

More terms from _R. J. Mathar (mathar(AT)strw.leidenuniv.nl), _, Apr 03 2008

Discussion
Fri Mar 30
17:39
OEIS Server: https://oeis.org/edit/global/190
#2 by Russ Cox at Fri Mar 30 17:25:28 EDT 2012
AUTHOR

_Gary W. Adamson (qntmpkt(AT)yahoo.com), _, Mar 28 2008

Discussion
Fri Mar 30
17:25
OEIS Server: https://oeis.org/edit/global/135
#1 by N. J. A. Sloane at Sun Jun 29 03:00:00 EDT 2008
NAME

a(n) = 4*a(n-1) - 3*a(n-2) + 2*a(n-3) - 1*a(n-4).

DATA

1, 1, 1, 2, 6, 19, 61, 197, 637, 2060, 6662, 21545, 69677, 225337, 728745, 2356778, 7621874, 24649315, 79716449, 257804821, 833746693, 2696355892, 8720076682, 28200927617, 91202445513, 294950796673, 953877628705, 3084862088210, 9976514614558, 32264276654339, 104343409321397, 337448974463477, 1091317708583837, 3529346452933372, 11413987225587534

OFFSET

1,4

COMMENTS

a(n)/a(n-1) tends to 3.2340228928..., an eigenvalue of the matrix X and a root to x^4 - 4*x^3 + 3*x^2 - 2*x + 1 = 0.

FORMULA

a(n) = 4*a(n-1) - 3*a(n-2) + 2*a(n-3) - 1*a(n-4); a>4. Let X = the 4 X 4 matrix [0,1,0,0; 0,0,1,0; 0,0,0,1; -1,2,-3,4]. X^n * [1,1,1,1] = [a(n), a(n+1), a(n+2), a(n+3)].

O.g.f.: -x(-1+3x+x^3)/(1-4x+3x^2-2x^3+x^4). - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 03 2008

EXAMPLE

a(7) = 61 = 4*a(6) - 3*a(5) + 2*a(4) - 1*a(3) = 4*19 - 3*6 + 2*2 - 1*1.

X^4 * [1,1,1,1] = [a(4), a(5), a(6), a(7)] = [2, 6, 19, 61].

KEYWORD

nonn

AUTHOR

Gary W. Adamson (qntmpkt(AT)yahoo.com), Mar 28 2008

EXTENSIONS

More terms from R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Apr 03 2008

STATUS

approved