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#17 by Harvey P. Dale at Sat Dec 04 12:42:10 EST 2021
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#16 by Harvey P. Dale at Sat Dec 04 12:42:07 EST 2021
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Harvey P. Dale, <a href="/A131352/b131352.txt">Table of n, a(n) for n = 0..1000</a>
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approved
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#15 by Harvey P. Dale at Sat Dec 04 12:40:54 EST 2021
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#14 by Harvey P. Dale at Sat Dec 04 12:40:51 EST 2021
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<a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (4,-4).
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CoefficientList[Series[(1-2x+2x^2-2x^3)/(1-2x)^2, {x, 0, 40}], x] (* or *) LinearRecurrence[{4, -4}, {1, 2, 6, 14}, 40] (* Harvey P. Dale, Dec 04 2021 *)
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approved
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#13 by Joerg Arndt at Sat Feb 15 12:31:47 EST 2014
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#12 by Jon E. Schoenfield at Sat Feb 15 11:31:17 EST 2014
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#11 by Jon E. Schoenfield at Sat Feb 15 11:31:15 EST 2014
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a(n) = 2^(n-2)*(n+4) for n>1. [_. - __Colin Barker_, JuneJun 05 2012]
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approved
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#10 by Bruno Berselli at Tue Jun 05 17:23:59 EDT 2012
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#9 by Bruno Berselli at Tue Jun 05 17:23:55 EDT 2012
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a(n)=) = A129954(n), n>1. G.f.: (1-2x+2x^2-2x^3)/(1-2x)^2. [From _. [_R. J. Mathar_, Dec 13 2008]
a(n)=) = 2^(n-2)*(n+4) for n>1. [Colin Barker, June 05 2012]
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#8 by Colin Barker at Tue Jun 05 14:04:24 EDT 2012
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