editing
approved
editing
approved
with(combinat): a:=proc(n) if type(fibonacci(fibonacci(n))/fibonacci(n), integer)=true then n else end if end proc: seq(a(n), n=1..40); # Emeric Deutsch, Aug 24 2007
Cf. A263101.
Comment from _Stefan Steinerberger_, Dec 20 2007: It is known that for n > 2 Fibonacci(n) divides Fibonacci(m) if and only if n divides m. Therefore if the term "2" is omitted this is identical to A023172, which see for further information. - _Stefan Steinerberger_, Dec 20 2007
with(combinat): a:=proc(n) if type(fibonacci(fibonacci(n))/fibonacci(n), integer)=true then n else end if end proc: seq(a(n), n=1..40); - _# _Emeric Deutsch_, Aug 24 2007
approved
editing
_Alexander Adamchuk (alex(AT)kolmogorov.com), _, May 13 2007
Comment from _Stefan Steinerberger (stefan.steinerberger(AT)gmail.com), _, Dec 20 2007: It is known that for n > 2 Fibonacci(n) divides Fibonacci(m) if and only if n divides m. Therefore if the term "2" is omitted this is identical to A023172, which see for further information.
with(combinat): a:=proc(n) if type(fibonacci(fibonacci(n))/fibonacci(n), integer)=true then n else end if end proc: seq(a(n), n=1..40); - _Emeric Deutsch (deutsch(AT)duke.poly.edu), _, Aug 24 2007
Edited by _N. J. A. Sloane (njas(AT)research.att.com), _, Dec 22 2007
Comment from Stefan Steinerberger (stefan.steinerberger(AT)gmail.com>, ), Dec 20 2007: It is known that for n > 2 Fibonacci(n) divides Fibonacci(m) if and only if n divides m. Therefore if the term "2" is omitted this is identical to A023172, which see for further information.
nonn,new
nonn
nonn,new
nonn
Edited by N. J. A. Sloane (njas, (AT)research.att.com), Dec 22 2007