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#11 by Bruno Berselli at Thu Jun 01 12:06:26 EDT 2017
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#10 by Joerg Arndt at Thu Jun 01 09:12:23 EDT 2017
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#9 by Colin Barker at Thu Jun 01 06:46:28 EDT 2017
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#8 by Colin Barker at Thu Jun 01 06:46:09 EDT 2017
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| COMMENTS
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[Empirical] a(base,n)=a(base-1,n)+9^(n-1) for base>=4n-3; a(base,n)=a(base-1,n)+9^(n-1)-2 when base=4n-4.
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| FORMULA
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Conjectures from Colin Barker, Jun 01 2017: (Start)
G.f.: (1 + 2*x - x^2 - x^3) / (1 - 6*x - 5*x^2 + 3*x^3 + 2*x^4).
a(n) = 6*a(n-1) + 5*a(n-2) - 3*a(n-3) - 2*a(n-4) for n>3.
(End)
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| STATUS
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approved
editing
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#7 by Russ Cox at Sat Mar 31 12:35:06 EDT 2012
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| AUTHOR
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_R. H. Hardin (rhhardin(AT)att.net), _, Dec 28 2006
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Discussion
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| Sat Mar 31
| 12:35
| OEIS Server: https://oeis.org/edit/global/875
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#6 by Charles R Greathouse IV at Fri Nov 12 23:52:47 EST 2010
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#5 by Charles R Greathouse IV at Fri Nov 12 23:52:43 EST 2010
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| KEYWORD
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nonn,newbase
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| STATUS
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approved
proposed
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#4 by N. J. A. Sloane at Sat Oct 02 03:00:00 EDT 2010
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| KEYWORD
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nonn,new
nonn
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| AUTHOR
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Ron R. H. Hardin (rhhardin(AT)att.net), Dec 28 2006
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#3 by N. J. A. Sloane at Fri Jan 09 03:00:00 EST 2009
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| KEYWORD
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nonn,new
nonn
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| AUTHOR
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Ron Hardin (rhhrhhardin(AT)cadenceatt.comnet), Dec 28 2006
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#2 by N. J. A. Sloane at Sat Nov 10 03:00:00 EST 2007
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| COMMENTS
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[empiricalEmpirical] a(base,n)=a(base-1,n)+9^(n-1) for base>=4n-3; a(base,n)=a(base-1,n)+9^(n-1)-2 when base=4n-4
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| KEYWORD
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nonn,new
nonn
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