STATUS
reviewed
approved
reviewed
approved
proposed
reviewed
editing
proposed
Limit_{n->oo} a(n+1)/a(n) -> = 3*((1+sqrt(5))/2 if n ->infinity.
approved
editing
editing
approved
a(n) = (1/2)*((3/2)+(3/2)*sqrt(5))^n+(1/10)*((3/2)+(3/2)*sqrt(5))^n*sqrt(5)-(1/10)*sqrt(5)*((3/2)-(3/2)*sqrt(5))^n+(1/2)*((3/2)-(3/2)*sqrt(5))^n, with n >= 0. - Paolo P. Lava, Nov 19 2008
approved
editing
(MAGMAMagma) [3^n*Fibonacci(n+1): n in [0..25]]; // G. C. Greubel, Oct 03 2019
editing
approved
LinearRecurrence[{3, 9}, {1, 3}, 30] (* Harvey P. Dale, Apr 28 2020 *)
approved
editing
(Sage) [lucas_number1(n, 3, -9) for n in xrangerange(1, 23)] # Zerinvary Lajos, Apr 22 2009