proposed
approved
proposed
approved
editing
proposed
1, 1, 2, 1, 6, 4, 1, 24, 210, 8, 1, 120, 332640, 32760, 16, 1, 720, 29059430400, 19275223968000, 20389320, 32, 1, 5040, 223016017416192000, 1250004633476421848894668800000, 28844656968251942737920000, 48920775120, 64
1
1 2
1 6 4
1 24 210 8
1 120 332640 32760 16
1 3 3 1
1 (2*3*4) (5*6*7) 8 or (1 24 210 8)
(PARI) A112356(n)= { local(resul, piv, a); resul=[1]; piv=2; for(col=1, n, a=piv; piv++; for(c=2, binomial(n, col), a *= piv; piv++; ); resul=concat(resul, a); ); return(resul); } { for(row=0, 7, print(A112356(row)); ); } - _R. J. Mathar_, May 19 2006
{ for(row=0, 7, print(A112356(row)); ); } \\ R. J. Mathar, May 19 2006
approved
editing
_Amarnath Murthy (amarnath_murthy(AT)yahoo.com), _, Sep 05 2005
easy,nonn,tabl,new
easy,nonn,tabl,new
Following triangle is based on Pascal's triangle. The r-th term of the n-th row is product of C(n,r) successive integers so such that the product of all the terms of the row is (2^n)!. Sequence contains the triangle read by rows.
1, 1, 2, 1, 6, 4, 1, 24, 210, 8, 1, 120, 332640, 32760, 16, 1, 720, 29059430400, 19275223968000, 20389320, 32, 1, 5040, 223016017416192000, 1250004633476421848894668800000, 28844656968251942737920000, 48920775120
easy,more,nonn,tabl,new
More terms from Mandy Stoner (astoner(AT)ashland.edu), Apr 27 2006
Following triangle is based on Pascal's triangle. The r-th term of the n-th row is product of C(n,r) successive integers so that the product of all the terms of the row is (2^n)!. Sequence contains the triangle read by rows.
1, 1, 2, 1, 6, 4, 1, 24, 210, 8, 1, 120, 332640, 32760, 16
0,3
The leading diagonal contains 2^n. The second column terms are (n+1)!.
Triangle begins:
1
1 2
1 6 4
1 24 210 8
1 120 332640 32760 16
...
The row for n = 3 is
1 3 3 1
1 (2*3*4) (5*6*7) 8 or (1 24 210 8)
Cf. A112357.
easy,more,nonn,tabl
Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Sep 05 2005
approved