The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A110766 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
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A110766

Fractalization of Pi.
(history; published version)

#12 by Alois P. Heinz at Fri Feb 26 17:03:48 EST 2021

STATUS

proposed

approved

#11 by Robert C. Lyons at Fri Feb 26 16:53:54 EST 2021

STATUS

editing

proposed

#10 by Robert C. Lyons at Fri Feb 26 16:53:44 EST 2021

NAME

Fractalisation Fractalization of Pi.

STATUS

approved

editing

#9 by Joerg Arndt at Sat Jan 30 02:19:19 EST 2021

STATUS

proposed

approved

#8 by Michel Marcus at Sat Jan 30 00:34:40 EST 2021

STATUS

editing

proposed

#7 by Michel Marcus at Sat Jan 30 00:34:35 EST 2021

LINKS

C. Clark Kimberling, <a href="http://faculty.evansville.edu/ck6/integer/fractals.html">Fractal sequences</a>.

CROSSREFS

Cf. A000796 (Pi), A003602.

Cf. A000796.

STATUS

approved

editing

#6 by Reinhard Zumkeller at Fri Aug 29 07:09:09 EDT 2014

STATUS

editing

approved

#5 by Reinhard Zumkeller at Fri Aug 29 07:08:57 EDT 2014

FORMULA

a(2n) = a(n); a(2n-1) = digits of Pi.

CROSSREFS

Cf. A000796.

#4 by Reinhard Zumkeller at Fri Aug 29 02:29:01 EDT 2014

FORMULA

a(2n)=a(n); a(2n+-1)=digits of Pi

PROG

(Haskell)

import Data.List (transpose)

a110766 n = a110766_list !! (n-1)

a110766_list = concat $ transpose [a000796_list, a110766_list]

-- Reinhard Zumkeller, Aug 29 2014

CROSSREFS

Cf. A000796.

EXTENSIONS

a(85) corrected and formula fixed by Reinhard Zumkeller, Aug 29 2014

Discussion

Fri Aug 29

02:29

Reinhard Zumkeller: a(85) = A000796(2-(85+1)/2) = A000796(2-43) = A000796(41) = 9, not = 2.

#3 by Reinhard Zumkeller at Fri Aug 29 02:26:30 EDT 2014

DATA

3, 3, 1, 3, 4, 1, 1, 3, 5, 4, 9, 1, 2, 1, 6, 3, 5, 5, 3, 4, 5, 9, 8, 1, 9, 2, 7, 1, 9, 6, 3, 3, 2, 5, 3, 5, 8, 3, 4, 4, 6, 5, 2, 9, 6, 8, 4, 1, 3, 9, 3, 2, 8, 7, 3, 1, 2, 9, 7, 6, 9, 3, 5, 3, 0, 2, 2, 5, 8, 3, 8, 5, 4, 8, 1, 3, 9, 4, 7, 4, 1, 6, 6, 5, 29

LINKS

Reinhard Zumkeller, <a href="/A110766/b110766.txt">Table of n, a(n) for n = 1..10000</a>

STATUS

approved

editing