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#11 by Michel Marcus at Thu Mar 11 04:37:19 EST 2021
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#10 by Joerg Arndt at Thu Mar 11 04:17:52 EST 2021
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#9 by Petros Hadjicostas at Thu Mar 11 03:35:09 EST 2021
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#8 by Petros Hadjicostas at Thu Mar 11 03:32:53 EST 2021
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| FORMULA
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a(n) = Sum_{r=1..(n+1)} (-1)^(r-1) * Sum_{s_1, ..., s_r} (s_1^(-1)/(Product_{j=1..r} s_j!)) * Product_{j=1..r} (Sum_{i=1..j} s_i)^(3*s_j)), where the second sum is over lists (s_1, ..., s_r) of positive integers s_i such that Sum_{i=1..r} s_i = n + 1. (Thus, the second sum is over all compositions of n + 1.) - Petros Hadjicostas, Mar 11 2021
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| STATUS
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approved
editing
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Discussion
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Thu Mar 11
| 03:34
| Petros Hadjicostas: Replacing s_1^{-1} with other powers of s_1 (positive or negative) essentially gives column 0 in powers of T... (Robinson had s_1; I used other powers: 0, -1, etc.).
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#7 by N. J. A. Sloane at Thu Mar 11 03:04:35 EST 2021
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#6 by Joerg Arndt at Thu Mar 11 01:58:00 EST 2021
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#5 by Petros Hadjicostas at Thu Mar 11 01:46:14 EST 2021
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#4 by Petros Hadjicostas at Thu Mar 11 01:46:08 EST 2021
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| FORMULA
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a(n) = (n+1)^3*A107672A107673(n).). [Corrected by _Petros Hadjicostas_, Mar 11 2021]
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| STATUS
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approved
editing
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#3 by Russ Cox at Fri Mar 30 18:36:46 EDT 2012
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| AUTHOR
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_Paul D. Hanna (pauldhanna(AT)juno.com), _, Jun 07 2005
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Discussion
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Fri Mar 30
| 18:36
| OEIS Server: https://oeis.org/edit/global/213
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#2 by N. J. A. Sloane at Sat Nov 10 03:00:00 EST 2007
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| KEYWORD
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nonn,new
nonn
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| AUTHOR
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Paul D . Hanna (pauldhanna(AT)juno.com), Jun 07 2005
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