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Revision History for A106247 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

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Expansion of (1+2*x-x^2-2*x^3+x^4) / (1-x^2)^3.
(history; published version)
#8 by Harvey P. Dale at Thu Mar 23 09:25:13 EDT 2023
STATUS

editing

approved

#7 by Harvey P. Dale at Thu Mar 23 09:25:09 EDT 2023
MATHEMATICA

CoefficientList[Series[(1+2x-x^2-2x^3+x^4)/(1-x^2)^3, {x, 0, 100}], x] (* or *) LinearRecurrence[{0, 3, 0, -3, 0, 1}, {1, 2, 2, 4, 4, 6}, 100] (* Harvey P. Dale, Mar 23 2023 *)

STATUS

approved

editing

#6 by Bruno Berselli at Sat Jul 23 10:10:24 EDT 2016
STATUS

proposed

approved

#5 by Colin Barker at Sat Jul 23 09:57:50 EDT 2016
STATUS

editing

proposed

#4 by Colin Barker at Sat Jul 23 09:56:57 EDT 2016
NAME

Expansion of (1+2x2*x-x^2-2x2*x^3+x^4) / (1-x^2)^3.

LINKS

Colin Barker, <a href="/A106247/b106247.txt">Table of n, a(n) for n = 0..1000</a>

<a href="/index/Rec#order_06">Index entries for linear recurrences with constant coefficients</a>, signature (0,3,0,-3,0,1).

FORMULA

From Colin Barker, Jul 23 2016: (Start)

a(n) = (16+10*n+(-1)^n*(-6+n)*n+n^2)/16.

a(n) = (n^2+2*n+8)/8 for n even.

a(n) = n+1 for n odd.

a(n) = 3*a(n-2)-3*a(n-4)+a(n-6) for n>5.

(End)

PROG

(PARI) Vec((1+2*x-x^2-2*x^3+x^4)/(1-x^2)^3 + O(x^100)) \\ Colin Barker, Jul 23 2016

STATUS

approved

editing

#3 by Russ Cox at Fri Mar 30 18:59:07 EDT 2012
AUTHOR

_Paul Barry (pbarry(AT)wit.ie), _, Apr 26 2005

Discussion
Fri Mar 30
18:59
OEIS Server: https://oeis.org/edit/global/287
#2 by N. J. A. Sloane at Fri Feb 24 03:00:00 EST 2006
FORMULA

a(n)=sum{k=0..floor(n/2), C(n-k, k)C(2, n-2k)}; a(2n)=A000124(n); a(2n+1)=A005843(n+1).

KEYWORD

easy,nonn,new

#1 by N. J. A. Sloane at Tue Jul 19 03:00:00 EDT 2005
NAME

Expansion of (1+2x-x^2-2x^3+x^4)/(1-x^2)^3.

DATA

1, 2, 2, 4, 4, 6, 7, 8, 11, 10, 16, 12, 22, 14, 29, 16, 37, 18, 46, 20, 56, 22, 67, 24, 79, 26, 92, 28, 106, 30, 121, 32, 137, 34, 154, 36, 172, 38, 191, 40, 211, 42, 232, 44, 254, 46, 277, 48, 301, 50, 326, 52, 352, 54, 379, 56, 407, 58, 436, 60, 466, 62, 497, 64, 529, 66

OFFSET

0,2

COMMENTS

Diagonal sums of number triangle A106246. Transform of C(2,n)=(1,2,1,0,0,0,...) under the mapping that takes g(x) to (1/(1-x^2))g(x/(1-x^2)).

FORMULA

a(n)=sum{k=0..floor(n/2), C(n-k,k)C(2,n-2k)}; a(2n)=A000124(n); a(2n+1)=A005843(n+1).

KEYWORD

easy,nonn

AUTHOR

Paul Barry (pbarry(AT)wit.ie), Apr 26 2005

STATUS

approved