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Revision History for A077136 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Composite numbers n whose proper divisors (excluding 1 and n) are all of the form p or p+1, with p prime.
(history; published version)
#13 by Giovanni Resta at Tue Dec 10 04:00:37 EST 2019
STATUS

reviewed

approved

#12 by Michel Marcus at Tue Dec 10 03:55:46 EST 2019
STATUS

proposed

reviewed

#11 by Amiram Eldar at Tue Dec 10 03:48:43 EST 2019
STATUS

editing

proposed

#10 by Amiram Eldar at Tue Dec 10 03:33:32 EST 2019
MATHEMATICA

seqQ[n_] := CompositeQ[n] && AllTrue[Most @ Rest @ Divisors[n], PrimeQ[#] || PrimeQ[# - 1] &]; Select[Range[161], seqQ] (* Amiram Eldar, Dec 10 2019 *)

#9 by Amiram Eldar at Tue Dec 10 03:32:12 EST 2019
LINKS

Amiram Eldar, <a href="/A077136/b077136.txt">Table of n, a(n) for n = 1..10000</a>

STATUS

approved

editing

#8 by N. J. A. Sloane at Thu Dec 05 19:55:48 EST 2013
AUTHOR

_Amarnath Murthy (amarnath_murthy(AT)yahoo.com), _, Oct 29 2002

Discussion
Thu Dec 05
19:55
OEIS Server: https://oeis.org/edit/global/2075
#7 by Russ Cox at Fri Mar 30 18:41:14 EDT 2012
EXTENSIONS

Corrected and extended by _Ralf Stephan (ralf(AT)ark.in-berlin.de), _, Mar 23 2003

Discussion
Fri Mar 30
18:41
OEIS Server: https://oeis.org/edit/global/233
#6 by Russ Cox at Fri Mar 30 17:35:15 EDT 2012
COMMENTS

The only numbers in the sequence that are neither a semiprime nor of the form 4p (where 2p-1 is also prime) are 16 and 24. If n has pq as a proper divisor, with p and q odd primes (not necessarily distinct), neither pq nor pq-1 can be prime. Likewise 16 cannot be a proper factor. Other than the two specified cases, this leaves n = 8p, where 2p-1 and 4p-1 are primes. p = 2 or 3 gives the exceptional cases 16 and 24, respectively. Any other prime must be == 1 or 2 (mod 3); if 1, then 4p-1 is divisible by 3 and if 2, then 2p-1 is divisible by 3. - _Franklin T. Adams-Watters (FrankTAW(AT)Netscape.net), _, Jul 28 2007

Discussion
Fri Mar 30
17:35
OEIS Server: https://oeis.org/edit/global/165
#5 by N. J. A. Sloane at Fri Feb 27 03:00:00 EST 2009
COMMENTS

The only numbers in the sequence that are neither a semiprime nor of the form 4p (where 2p-1 is also prime) are 16 and 24. If n has pq as a proper divisor, with p and q odd primes (not necessarily distinct), neither pq nor pq-1 can be prime. Likewise 16 cannot be a proper factor. Other than the two specified cases, this leaves n = 8p, where 2p-1 and 4p-1 are primes. p = 2 or 3 gives the exceptional cases 16 and 24, respectively. Any other prime must be == 1 or 2 (mod 3); if 1, then 4p-1 is divisible by 3, and if 2, then 2p-1 is divisible by 3. - Franklin T. Adams-Watters (FrankTAW(AT)Netscape.net), Jul 28 2007

KEYWORD

nonn,new

nonn

#4 by N. J. A. Sloane at Fri Jan 09 03:00:00 EST 2009
PROG

(PARI) for(n=1, 200, v=divisors(n):s=0:for(k=2, length(v)-1, if(isprime(v[k])||isprime(v[k]-1), s=s+1)): if(s&&s==length(v)-2, print1(n", ")))

KEYWORD

nonn,new

nonn