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Numbers n that divide the concatenation of n+1 and n+2.
(history; published version)
#7 by N. J. A. Sloane at Thu Dec 05 19:55:18 EST 2013
AUTHOR

_Amarnath Murthy (amarnath_murthy(AT)yahoo.com), _, Apr 18 2002

Discussion
Thu Dec 05
19:55
OEIS Server: https://oeis.org/edit/global/2075
#6 by Russ Cox at Sat Mar 31 13:20:45 EDT 2012
FORMULA

For k > 0, sequence contains (10^k+2)/2, (10^k+2)/3, (10^k+2)/6 and (10^(6k-1)+2)/7. The only other terms are 1 and 3. - _David Wasserman (wasserma(AT)spawar.navy.mil), _, Aug 25 2005

EXTENSIONS

More terms from _David Wasserman (wasserma(AT)spawar.navy.mil), _, Aug 25 2005

Discussion
Sat Mar 31
13:20
OEIS Server: https://oeis.org/edit/global/880
#5 by Russ Cox at Fri Mar 30 17:30:43 EDT 2012
EXTENSIONS

Edited and extended by _Robert G. Wilson v (rgwv(AT)rgwv.com), _, Apr 22 2002

Discussion
Fri Mar 30
17:30
OEIS Server: https://oeis.org/edit/global/156
#4 by N. J. A. Sloane at Fri Feb 27 03:00:00 EST 2009
FORMULA

For k > 0, sequence contains (10^k+2)/2, (10^k+2)/3, (10^k+2)/6, and (10^(6k-1)+2)/7. The only other terms are 1 and 3. - David Wasserman (wasserma(AT)spawar.navy.mil), Aug 25 2005

KEYWORD

base,nonn,new

#3 by N. J. A. Sloane at Wed Sep 21 03:00:00 EDT 2005
DATA

1, 2, 3, 4, 6, 17, 34, 51, 167, 334, 501, 1667, 3334, 5001, 14286, 16667, 33334, 50001, 166667, 333334, 500001, 1666667, 3333334, 5000001, 16666667, 33333334, 50000001, 166666667, 333333334, 500000001, 1666666667, 3333333334

COMMENTS

With the exception of the first term (1), each term in this sequence also evenly divides the number formed by concatenating (n-1) and (n-2). So, for example, 17 divides evenly into both 1819 and 1615. There do not appear to be any terms such that n divides evenly into the concatenation of (n-1) and (n-2) that are not included in this sequence. - Chuck Seggelin (barkeep(AT)plastereddragon.com), Oct 18 2003

For values of n with 3 digits or more, an apparent pattern arises such that the terms 1(6)...7, 3(3)...4, and 5(0)...1 are members of the sequence for each successive power of 10. The only exception to this in the terms given above is 14286. Cases like this only seem to arise when the term 16...7 is divisible by 7. Let x=16...7. If 7 divides x, then x/7*6 is a term. This works for 16667 since 16667 = 7*2381 and 14286 = 6*2381. The next n of the form 16...7 that is divisible by 7 is 16666666667 (7 * 2380952381), 16666666667/7*6 = 14285714286 and 14285714286 is a member of this sequence. 16666666666666667 is also divisible by 7 and 16666666666666667/7*6 = 14285714285714286 and 14285714285714286 is a member of this sequence. Note the similarity between terms of the form (142857)...14286 and the floating point representation of the fraction 1/7 (.142857142857142857...) - Chuck Seggelin (barkeep(AT)plastereddragon.com), Oct 18 2003

FORMULA

For k > 0, sequence contains (10^k+2)/2, (10^k+2)/3, (10^k+2)/6, and (10^(6k-1)+2)/7. The only other terms are 1 and 3. - David Wasserman (wasserma(AT)spawar.navy.mil), Aug 25 2005

KEYWORD

base,nonn,new

EXTENSIONS

More terms from David Wasserman (wasserma(AT)spawar.navy.mil), Aug 25 2005

#2 by N. J. A. Sloane at Thu Feb 19 03:00:00 EST 2004
COMMENTS

With the exception of the first term (1), each term in this sequence also evenly divides the number formed by concatenating (n-1) and (n-2). So, for example, 17 divides evenly into both 1819 and 1615. There do not appear to be any terms such that n divides evenly into the concatenation of (n-1) and (n-2) that are not included in this sequence. - Chuck Seggelin (barkeep(AT)plastereddragon.com), Oct 18 2003

For values of n with 3 digits or more, an apparent pattern arises such that the terms 1(6)...7, 3(3)...4, and 5(0)...1 are members of the sequence for each successive power of 10. The only exception to this in the terms given above is 14286. Cases like this only seem to arise when the term 16...7 is divisible by 7. Let x=16...7. If 7 divides x, then x/7*6 is a term. This works for 16667 since 16667 = 7*2381 and 14286 = 6*2381. The next n of the form 16...7 that is divisible by 7 is 16666666667 (7 * 2380952381), 16666666667/7*6 = 14285714286 and 14285714286 is a member of this sequence. 16666666666666667 is also divisible by 7 and 16666666666666667/7*6 = 14285714285714286 and 14285714285714286 is a member of this sequence. Note the similarity between terms of the form (142857)...14286 and the floating point representation of the fraction 1/7 (.142857142857142857...) - Chuck Seggelin (barkeep(AT)plastereddragon.com), Oct 18 2003

MATHEMATICA

Select[ Range[10^7], IntegerQMod[ ToExpressionFromDigits[ StringJoinJoin[ ToStringIntegerDigits[ # + 1], ToStringIntegerDigits[ # + 2]]] / , # ] == 0 & ]

KEYWORD

base,nonn,new

#1 by N. J. A. Sloane at Fri May 16 03:00:00 EDT 2003
NAME

Numbers n that divide the concatenation of n+1 and n+2.

DATA

1, 2, 3, 4, 6, 17, 34, 51, 167, 334, 501, 1667, 3334, 5001, 14286, 16667, 33334, 50001, 166667, 333334, 500001, 1666667, 3333334, 5000001

OFFSET

1,2

EXAMPLE

17 divides 1819 hence is a member.

MATHEMATICA

Select[ Range[10^7], IntegerQ[ ToExpression[ StringJoin[ ToString[ # + 1], ToString[ # + 2]]] / # ] & ]

CROSSREFS
KEYWORD

base,nonn

AUTHOR

Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Apr 18 2002

EXTENSIONS

Edited and extended by Robert G. Wilson v (rgwv(AT)rgwv.com), Apr 22 2002

STATUS

approved