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#28 by Alois P. Heinz at Tue Aug 18 10:39:22 EDT 2020
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#27 by Alois P. Heinz at Tue Aug 18 10:35:20 EDT 2020
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a(8) = 48. If nonzero, a(7) > 2*10^7.
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Discussion
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| Tue Aug 18
| 10:35
| Alois P. Heinz: both values in DATA now ...
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#26 by Alois P. Heinz at Tue Aug 18 10:32:35 EDT 2020
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base,nonn,fini,full,changed
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proposed
editing
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Discussion
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| Tue Aug 18
| 10:33
| Alois P. Heinz: we have an infinite number of values 0. So this is not full.
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| 10:34
| Alois P. Heinz: also a(7)=0 is known.
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| 10:35
| Alois P. Heinz: we should reduce redundancy ...
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#25 by Joerg Arndt at Tue Aug 18 10:23:53 EDT 2020
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#24 by Joerg Arndt at Tue Aug 18 10:23:48 EDT 2020
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base,nonn,fini,full,changed
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| STATUS
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proposed
editing
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#23 by David A. Corneth at Tue Aug 18 10:21:36 EDT 2020
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#22 by David A. Corneth at Tue Aug 18 10:18:28 EDT 2020
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| COMMENTS
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a(8) = 48. If nonzero, a(7) > 2*10^7 and a(9) > 10^7.
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| STATUS
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proposed
editing
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Discussion
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| Tue Aug 18
| 10:19
| David A. Corneth: the comment below what I removed says a(9) = 0.
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| 10:21
| David A. Corneth: we can push the lower bound on a(7), if nonzero, using A009994 right? Just as order of digits doesn't matter both for their product and their sum.
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#21 by Michel Marcus at Tue Aug 18 10:14:52 EDT 2020
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#20 by Michel Marcus at Tue Aug 18 10:14:39 EDT 2020
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| COMMENTS
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a(8) = 48. If nonzero, a(7) > 2 *10^7 and a(9) > 10^7.
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| STATUS
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proposed
editing
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#19 by Robert Israel at Tue Aug 18 10:09:51 EDT 2020
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Discussion
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| Tue Aug 18
| 10:10
| Robert Israel: Thanks for catching that.
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