(MAGMAMagma) [(n^4 + 22*n^3 + 105*n^2 - 56*n - 8)/4: n in [1..40]]; // Vincenzo Librandi, Jul 03 2018
(MAGMAMagma) [(n^4 + 22*n^3 + 105*n^2 - 56*n - 8)/4: n in [1..40]]; // Vincenzo Librandi, Jul 03 2018
E. J. Friedman, <a href="httphttps://wwwerich-friedman.stetsongithub.edu/~efriedmaio/mathmagic/0599.html">Math
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LinearRecurrence[{5, -10, 10, -5, 1}, {16, 123, 361, 778, 1428}, 50] (* Harvey P. Dale, Dec 24 2019 *)
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reviewed
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16, 123, 361, 778, 1428, 2371, 3673, 5406, 7648, 10483, 14001, 18298, 23476, 29643, 36913, 45406, 55248, 66571, 79513, 94218, 110836, 129523, 150441, 173758, 199648, 228291, 259873, 294586, 332628, 374203, 419521, 468798, 522256, 580123, 642633, 710026, 782548, 860451
a(n) = (n^4 + 22n22*n^3 + 105n105*n^2 - 56n 56*n - 8)/4.
Table[(n^4 + 22 n^3 + 105 n^2 - 56 n - 8) / 4, {n, 40}] (* Vincenzo Librandi, Jul 03 2018 *)
(MAGMA) [(n^4 + 22*n^3 + 105*n^2 - 56*n - 8)/4: n in [1..40]]; // Vincenzo Librandi, Jul 03 2018
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(PARI) { for a(n)=1, 1000, write("b060633.txt", n, " ", {(n^4 + 22*n^3 + 105*n^2 - 56*n - 8)/4); ) } \\ Harry J. Smith, Jul 08 2009
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