editing
approved
editing
approved
S. Steven R. Finch, Mathematical Constants, Cambridge, 2003, pp. 354-361.
S. Steven R. Finch, <a href="http://www.people.fas.harvard.edu/~sfinch/constant/digcntfrc/digmnkwskDigital Search Tree ConstantsMinkowski's Question Mark Function</a> [Broken link]
Steven R. Finch, <a href="http://web.archive.org/web/20010208143502/http://www.mathsoft.com/asolve/constant
approved
editing
proposed
approved
editing
proposed
Continued fraction expansion of the constant Product{k>=1..inf} (1-1/2^k)^(-1) = 3.46274661945506361... (A065446) gives essentially the same sequence.
Harry J. Smith, <a href="/A048652/b048652.txt">Table of n, a(n) for n = 0,...,20000</a>
0.288788095086602421278899721... = 0 + 1/(3 + 1/(2 + 1/(6 + 1/(4 + ...)))) [From _. - _Harry J. Smith_, May 02 2009]
(PARI) { allocatemem(932245000); default(realprecision, 21000); x=prodinf(k=1, -1/2^k, 1); z=contfrac(x); for (n=1, 20001, write("b048652.txt", n-1, " ", z[n])); } [From _\\ _Harry J. Smith_, May 07 2009]
Deleted old PARI program _. - _Harry J. Smith_, May 20 2009
approved
editing
S. R. Finch, <a href="http://algowww.people.fas.inriaharvard.fredu/bsolve~sfinch
0.288788095086602421278899721... = 0 + 1/(3 + 1/(2 + 1/(6 + 1/(4 + ...)))) [From _Harry J. Smith (hjsmithh(AT)sbcglobal.net), _, May 02 2009]
(PARI) { allocatemem(932245000); default(realprecision, 21000); x=prodinf(k=1, -1/2^k, 1); z=contfrac(x); for (n=1, 20001, write("b048652.txt", n-1, " ", z[n])); } [From _Harry J. Smith (hjsmithh(AT)sbcglobal.net), _, May 07 2009]
Corrected by _Harry J. Smith (hjsmithh(AT)sbcglobal.net), _, May 02 2009
Deleted old PARI program _Harry J. Smith (hjsmithh(AT)sbcglobal.net), _, May 20 2009
_N. J. A. Sloane (njas(AT)research.att.com)_.
<a href="/Sindx_index/Con.html#confC">Index entries for continued fractions for constants</a>
Harry J. Smith, <a href="/A048652/b048652.txt">Table of n, a(n) for n=0,...,20000</a>
<a href="/Sindx_Con.html#confC">Index entries for continued fractions for constants</a>
nonn,cofr,new