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#18 by Joerg Arndt at Sat Dec 30 23:47:43 EST 2023
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#17 by Paolo P. Lava at Sat Dec 30 12:50:00 EST 2023
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| FORMULA
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a(n) = 1+[1/2+(1/2)*sqrt(5)]^n+(2/5)*[1/2+(1/2)*sqrt(5)]^n*sqrt(5)-(2/5)*sqrt(5)*[1/2-(1/2) *sqrt(5)]^n+[1/2-(1/2)*sqrt(5)]^n, with n>0=0 - Paolo P. Lava, Jun 10 2008
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| STATUS
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approved
editing
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#16 by Charles R Greathouse IV at Thu Sep 08 08:44:57 EDT 2022
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| PROG
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(MAGMAMagma) [Fibonacci(n+3)+1: n in [0..40]]; // Vincenzo Librandi, Apr 27 2012
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Discussion
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| Thu Sep 08
| 08:44
| OEIS Server: https://oeis.org/edit/global/2944
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#15 by Joerg Arndt at Fri Apr 27 03:02:46 EDT 2012
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#14 by Vincenzo Librandi at Fri Apr 27 02:49:07 EDT 2012
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#13 by Vincenzo Librandi at Fri Apr 27 02:48:48 EDT 2012
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| LINKS
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Vincenzo Librandi, <a href="/A048577/b048577.txt">Table of n, a(n) for n = 0..1000</a>
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| MATHEMATICA
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CoefficientList[Series[(3-2*x-2*x^2)/((1-x)*(1-x-x^2)), {x, 0, 40}], x] (* Vincenzo Librandi, Apr 27 2012 *)
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| PROG
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(MAGMA) [Fibonacci(n+3)+1: n in [0..40]]; // Vincenzo Librandi, Apr 27 2012
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| STATUS
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approved
editing
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#12 by Charles R Greathouse IV at Mon Apr 16 11:11:36 EDT 2012
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#11 by Charles R Greathouse IV at Mon Apr 16 11:11:34 EDT 2012
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#10 by Colin Barker at Mon Apr 16 11:01:06 EDT 2012
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#9 by Colin Barker at Mon Apr 16 11:00:59 EDT 2012
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a(n)=) = 1+[1/2+(1/2)*sqrt(5)]^n+(2/5)*[1/2+(1/2)*sqrt(5)]^n*sqrt(5)-(2/5)*sqrt(5)*[1/2-(1/2) *sqrt(5)]^n+[1/2-(1/2)*sqrt(5)]^n, with n>0=0 - Paolo P. Lava, Jun 10 2008
a(n)=) = A020706(n-1), n>0. [From R. J. Mathar, Oct 15 2008]
G.f.: (3-2*x-2*x^2)/((1-x)*(1-x-x^2)). [Colin Barker, Apr 16 2012]
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| KEYWORD
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nonn,easy
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| STATUS
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approved
editing
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