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OEIS wiki, <a href="/wiki/Consecutive_primes_in_arithmetic_progression#CPAP_with_given
All terms p == 1 (mod 10) and hence p+24 are always divisible by 5. - Zak Seidov, Jun 20 2015
OEIS wiki, <a href="/wiki/Consecutive_primes_in_arithmetic_progression">Consecutive primes in arithmetic progression</a>, updated Jan. 2020
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Subsequence of A054800, with which is coincides up to a(24), but a(25) = A054800(26). - M. F. Hasler, Oct 26 2018
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251, 257, 263, 269 are consecutive primes: 257 = 251 + 6, 263 = 251 + 12, 269 = 251 + 18.
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N:=10^5: # to get all terms <= N.
Primes:=select(isprime, [seq(i, i=3..N+18, 2)]):
Primes[select(t->[Primes[t+1]-Primes[t], Primes[t+2]-Primes[t+1],
Primes[t+3]-Primes[t+2]]=[6, 6, 6], [$1..nops(Primes)-3])]; # Muniru A Asiru, Aug 04 2017
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