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a(n) = Sum_{c=0..floor(sqrt(n))} Sum_{i=0...n-c^2} A026820(i,c)*A026820(n-c^2-i,c). - David García Herrero, Aug 20 2024
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a(n) corresponds to is also the number of partitions of n*(n+3)/2 into n distinct parts. - David García Herrero, Aug 20 2024
For n>0, a(n) = Sum_{c=10..floor(sqrt(n))} Sum_{i=0...n-c^2} pA026820(i,c)*pA026820(n-c^2-i,c), where p(i,c) is the number of partitions of i into at most c parts. - David García Herrero, Aug 20 2024
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For n>0, a(n) = Sum_{c=1..floor(sqrt(n))} Sum_{i=0...n-c^2} p(i,c)*p(n-c^2-i,c), where p(i,c) is the number of partitions of i into at most c parts. - David García Herrero, Aug 20 2024
a(n) corresponds to the number of partitions of Nn(Nn+3)/2 into N n distinct parts. - David García Herrero, Aug 20 2024