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A367882 Table T(n, k) read by downward antidiagonals: T(n, k) = floor((4*T(n, k-1)+3)/3) starting with T(n, 0) = 4*n. 1
0, 1, 4, 2, 6, 8, 3, 9, 11, 12, 5, 13, 15, 17, 16, 7, 18, 21, 23, 22, 20, 10, 25, 29, 31, 30, 27, 24, 14, 34, 39, 42, 41, 37, 33, 28, 19, 46, 53, 57, 55, 50, 45, 38, 32, 26, 62, 71, 77, 74, 67, 61, 51, 43, 36, 35, 83, 95, 103, 99, 90, 82, 69, 58, 49, 40 (list; table; graph; refs; listen; history; text; internal format)
OFFSET
0,3
COMMENTS
Permutation of nonnegative numbers.
Let b(m) be the row n in which m appears, this sequence would start: 1, 1, 1, 1, 2, 1, 2, 1, 3, 2, 1, 3,... . If we would remove in this sequence the first appearance of each number then we would obtain again the same sequence, hence b(m) is a fractal sequence. - Thomas Scheuerle, Dec 04 2023
LINKS
Paolo Xausa, Table of n, a(n) for n = 0..11324 (first 150 antidiagonals, flattened).
FORMULA
T(n, 0) = 4*n = A008586(n).
T(3*n, 1) = 16*n + 1 = A158057(n).
T(3*n+1, 1) = 16*n + 6 = 2*A017101(n).
T(3*n+2, 1) = 16*n + 11 = A106839(n).
T(3^k+n, k) = 4^(k+1) + T(n, k). - Thomas Scheuerle, Dec 04 2023
EXAMPLE
Square array starts:
0, 1, 2, 3, 5, 7, ...
4, 6, 9, 13, 18, 25, ...
8, 11, 15, 21, 29, 39, ...
12, 17, 23, 31, 42, 57, ...
16, 22, 30, 41, 55, 74, ...
...
MATHEMATICA
A367882[n_, k_] := A367882[n, k] = If[k == 0, 4*n, Floor[4*A367882[n, k-1]/3 + 1]];
Table[A367882[k, n-k], {n, 0, 10}, {k, 0, n}] (* Paolo Xausa, Apr 03 2024 *)
PROG
(PARI) T(n, k) = if(k==0, 4*n, (4*T(n, k-1)+3)\3) \\ Thomas Scheuerle, Dec 04 2023
CROSSREFS
Sequence in context: A268718 A306874 A114478 * A330530 A302659 A363705
KEYWORD
nonn,tabl
AUTHOR
Philippe Deléham, Dec 04 2023
EXTENSIONS
More terms from Paolo Xausa, Apr 03 2024
STATUS
approved

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Last modified August 29 21:13 EDT 2024. Contains 375518 sequences. (Running on oeis4.)