OFFSET
1,4
EXAMPLE
a(1) = 0 since 1 is already at 1 which requires no iteration of the scheme;
a(2) = 1 since (1 + 2)/3 -> 1;
a(3) = 1 since 3/3 -> 1;
a(4) = 3 since 4 -> 8 -> (2+4)/3 -> 2 -> 1;
a(5) = 2 since 5 -> (1+5)/2 -> 2 -> 1;
a(6) = 2 since 6 -> 2 -> 1.
MATHEMATICA
f[n_] := f[n] = Switch[ Mod[n, 3], 0, n/3, 1, 2 n, 2, lst = Divisors@ n; len = Length@lst; (lst[[len/2]] + lst[[len/2 + 1]])/3]; a[n_] := Length@NestWhileList[f@# &, n, # > 1 &]; a[n_] := Length@ NestWhileList[f@# &, n, # > 1 &] - 1; Array[a, 105]
CROSSREFS
KEYWORD
nonn
AUTHOR
Ali Sada and Robert G. Wilson v, Jan 03 2021
STATUS
approved