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A309611
Digits of the 10-adic integer (-41/9)^(1/3).
3
1, 5, 3, 4, 0, 3, 5, 3, 0, 3, 6, 3, 0, 2, 6, 6, 9, 7, 3, 0, 6, 0, 1, 5, 2, 1, 1, 3, 8, 4, 4, 2, 8, 1, 5, 5, 9, 6, 3, 8, 1, 7, 8, 4, 0, 7, 9, 6, 1, 0, 4, 3, 5, 8, 4, 2, 7, 9, 8, 1, 0, 1, 6, 8, 8, 2, 6, 3, 1, 3, 8, 6, 2, 7, 4, 2, 8, 2, 2, 6, 2, 8, 2, 3, 0, 2, 8, 2, 9, 6, 8, 1, 2, 6, 8, 9, 3, 7, 6, 6
OFFSET
0,2
LINKS
FORMULA
Define the sequence {b(n)} by the recurrence b(0) = 0 and b(1) = 1, b(n) = b(n-1) + 7 * (9 * b(n-1)^3 + 41) mod 10^n for n > 1, then a(n) = (b(n+1) - b(n))/10^n
EXAMPLE
1^3 == 1 (mod 10).
51^3 == 51 (mod 10^2).
351^3 == 551 (mod 10^3).
4351^3 == 5551 (mod 10^4).
4351^3 == 55551 (mod 10^5).
304351^3 == 555551 (mod 10^6).
PROG
(PARI) N=100; Vecrev(digits(lift(chinese(Mod((-41/9+O(2^N))^(1/3), 2^N), Mod((-41/9+O(5^N))^(1/3), 5^N)))), N)
(Ruby)
def A309611(n)
ary = [1]
a = 1
n.times{|i|
b = (a + 7 * (9 * a ** 3 + 41)) % (10 ** (i + 2))
ary << (b - a) / (10 ** (i + 1))
a = b
}
ary
end
p A309611(100)
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Seiichi Manyama, Aug 10 2019
STATUS
approved