OFFSET
1,1
COMMENTS
LINKS
Chai Wah Wu, Table of n, a(n) for n = 1..1000
FORMULA
min(A050278(n)/2^k) = 3076521984/2^21 = 1467.
PROG
(Python)
from itertools import permutations
l = []
for d in permutations('0123456789', 10):
....if d[0] != '0':
........d2 = int(''.join(d))
........d = d2
........r = d2 % 2
........while not r:
............d2, r = divmod(d2, 2)
........l.append((d2, d))
l.sort()
A257893_list = [b for a, b in l] # Chai Wah Wu, May 24 2015
CROSSREFS
KEYWORD
nonn,base,fini
AUTHOR
Vladimir Shevelev and Peter J. C. Moses, May 12 2015
STATUS
approved