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A210216 Triangle of coefficients of polynomials v(n,x) jointly generated with A210215; see the Formula section. 3
1, 1, 2, 1, 3, 3, 1, 3, 7, 4, 1, 3, 8, 14, 5, 1, 3, 8, 20, 25, 6, 1, 3, 8, 21, 46, 41, 7, 1, 3, 8, 21, 54, 97, 63, 8, 1, 3, 8, 21, 55, 133, 189, 92, 9, 1, 3, 8, 21, 55, 143, 309, 344, 129, 10, 1, 3, 8, 21, 55, 144, 364, 674, 591, 175, 11, 1, 3, 8, 21, 55, 144, 376, 894 (list; table; graph; refs; listen; history; text; internal format)
OFFSET
1,3
COMMENTS
Limiting row: even-indexed Fibonacci numbers, A001906.
n-th row sum: -1+2*n
For a discussion and guide to related arrays, see A208510.
LINKS
FORMULA
u(n,x)=x*u(n-1,x)+v(n-1,x)+1,
v(n,x)=xu(n-1,x)+x*v(n-1,x)+1,
where u(1,x)=1, v(1,x)=1.
EXAMPLE
First five rows:
1
1...2
1...3...3
1...3...7...4
1...3...8...14...5
First three polynomials v(n,x): 1, 1 + 2x , 1 + 3x + 3x^2.
MATHEMATICA
u[1, x_] := 1; v[1, x_] := 1; z = 16;
u[n_, x_] := x*u[n - 1, x] + v[n - 1, x] + 1;
v[n_, x_] := x*u[n - 1, x] + x*v[n - 1, x] + 1;
Table[Expand[u[n, x]], {n, 1, z/2}]
Table[Expand[v[n, x]], {n, 1, z/2}]
cu = Table[CoefficientList[u[n, x], x], {n, 1, z}];
TableForm[cu]
Flatten[%] (* A210215 *)
Table[Expand[v[n, x]], {n, 1, z}]
cv = Table[CoefficientList[v[n, x], x], {n, 1, z}];
TableForm[cv]
Flatten[%] (* A210216 *)
Table[u[n, x] /. x -> 1, {n, 1, z}] (* A000225 *)
Table[v[n, x] /. x -> 1, {n, 1, z}] (* A000225 *)
Table[u[n, x] /. x -> -1, {n, 1, z}] (* A137470 *)
Table[v[n, x] /. x -> -1, {n, 1, z}] (* A137470 *)
CROSSREFS
Sequence in context: A278493 A209334 A180975 * A195915 A219158 A049834
KEYWORD
nonn,tabl
AUTHOR
Clark Kimberling, Mar 19 2012
STATUS
approved

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Last modified August 29 03:06 EDT 2024. Contains 375510 sequences. (Running on oeis4.)