OFFSET
1,1
COMMENTS
It appears that lim n ->infinity a(n)^(1/A069887(n)) = K (Khinchin constant = 2.68...) - Benoit Cloitre, Jan 29 2006
LINKS
Harvey P. Dale, Table of n, a(n) for n = 1..449
EXAMPLE
The continued fraction for (1+1/5)^5 is [2, 2, 20, 1, 9, 2, 3] and 2*2*20*1*9*2*3=4320 hence a(5)=4320
MATHEMATICA
Table[Times@@ContinuedFraction[(1+1/n)^n], {n, 20}] (* Harvey P. Dale, May 02 2019 *)
PROG
(PARI) for(n=1, 100, print1(prod(i=1, length(contfrac((1+1/n)^n)), component(contfrac((1+1/n)^n), i)), ", "))
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Benoit Cloitre, Jun 01 2002
STATUS
approved