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A069250
Sum of the reversals of the proper divisors of n.
5
0, 1, 1, 3, 1, 6, 1, 7, 4, 8, 1, 16, 1, 10, 9, 15, 1, 21, 1, 13, 11, 14, 1, 45, 6, 34, 13, 55, 1, 69, 1, 76, 15, 74, 13, 127, 1, 94, 35, 23, 1, 72, 1, 40, 69, 35, 1, 148, 8, 61, 75, 100, 1, 174, 17, 145, 95, 95, 1, 99, 1, 16, 32, 99, 37, 78, 1, 121, 36, 110, 1, 240, 1, 76, 112, 181, 19, 198, 1, 88, 85, 17, 1, 203
OFFSET
1,4
FORMULA
a(n) = A069192(n) - A004086(n). - Indranil Ghosh, Feb 10 2017
EXAMPLE
The proper divisors of 20 are 1,2,4,5,10, which reversed are 1,2,4,5,1, summing to 13. Therefore a(20) = 13.
MATHEMATICA
f[n_] := FromDigits[Reverse[IntegerDigits[n]]]; g[n_] := Apply[Plus, Map[f, Drop[Divisors[n], -1]]]; Table[g[i], {i, 1, 40}]
Table[Total[IntegerReverse/@Most[Divisors[n]]], {n, 100}] (* Requires Mathematica version 10 or later *) (* Harvey P. Dale, Apr 04 2021 *)
PROG
(Python)
def A069250(n):
....s=0
....for i in range(1, n):
........if n%i==0: s+=int(str(i)[::-1])
....return s # Indranil Ghosh, Feb 10 2017
CROSSREFS
KEYWORD
base,nonn
AUTHOR
Joseph L. Pe, Apr 19 2002
EXTENSIONS
More terms from N. J. A. Sloane, May 19 2013
STATUS
approved