8000 'filter' object has no attribute 'pop' · Issue #512 · tableau/server-client-python · GitHub
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mrreyes512 opened this issue Oct 18, 2019 · 4 comments
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'filter' object has no attribute 'pop' #512

mrreyes512 opened this issue Oct 18, 2019 · 4 comments
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@mrreyes512
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In the export.py line 46

I'm getting the below error...

Traceback (most recent call last):
  File "export.py", line 84, in <module>
    main()
  File "export.py", line 56, in main
    view = views.pop()
AttributeError: 'filter' object has no attribute 'pop'

I'm calling it as illustrated below:

python export.py --csv --file export1.csv `report_ID`

Do i need to specify any further information?
@andrewbcooper
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andrewbcooper commented Jan 8, 2020 •
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I had the same issue and found this on Stackoverflow. Are you using Python 3.x? If so, edit the code to be:

views = filter(lambda x: x.id == args.resource_id,
TSC.Pager(server.views.get))
views = list(views)
view = views.pop()

https://stackoverflow.com/questions/34820657/filter-object-has-no-attribute-pop

@JoeyKwok
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Mine returns 'IndexError: pop from empty list', using python 3.6 corrected with list.
I am using view.id as report_ID. Am I using the correct one?

@bcantoni bcantoni added the bug label Sep 1, 2020
@bcantoni
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bcantoni commented Sep 1, 2020

Confirmed this is still a bug in the sample. There are 2 issues here:

  • Making the sample work correctly in Python 3.x (as @andrewbcooper points out)
  • Better handling for the case where the resource_id is not found (as @JoeyKwok points out)

@jacalata jacalata mentioned this issue May 6, 2022
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@jacalata jacalata added the fixed label Jun 7, 2022
@jacalata
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jacalata commented Jun 7, 2022

The updated samples should cover this nicely.

@jacalata jacalata closed this as completed Jun 7, 2022
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@bcantoni @jacalata @mrreyes512 @andrewbcooper @JoeyKwok
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