8000 Misc cleanups and wording improvements for the itertools docs by rhettinger · Pull Request #119626 · python/cpython · GitHub
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Misc cleanups and wording improvements for the itertools docs #119626

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Tighten the wording for permutations(). Add links.
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rhettinger committed May 25, 2024
commit e42bf24990b4ee032fd4703f0d66d1c1f0c57111
26 changes: 9 additions & 17 deletions Doc/library/itertools.rst
Original file line number Diff line number Diff line change
Expand Up @@ -534,18 +534,24 @@ loops that truncate the stream.

.. function:: permutations(iterable, r=None)

Return successive *r* length permutations of elements in the *iterable*.
Return successive *r* length `permutations of elements
<https://www.britannica.com/science/permutation>`_ from the *iterable*.

If *r* is not specified or is ``None``, then *r* defaults to the length
of the *iterable* and all possible full-length permutations
are generated.

The output is a subsequence of :func:`product` where entries with
repeated elements have been filtered out. The length of the output is
given by :func:`math.perm` which gives ``n! / (n-r)!`` when ``0 <= r <=
n`` or zero when ``r > n``.

The permutation tuples are emitted in lexicographic order according to
the order of the input *iterable*. So, if the input *iterable* is sorted,
the order of the input *iterable*. If the input *iterable* is sorted,
the output tuples will be produced in sorted order.

Elements are treated as unique based on their position, not on their
value. So, if the input elements are unique, there will be no repeated
value. If the input elements are unique, there will be no repeated
values within a permutation.

Roughly equivalent to::
Expand Down Expand Up @@ -578,20 +584,6 @@ loops that truncate the stream.
else:
return

The code for :func:`permutations` can be also expressed as a subsequence of
:func:`product` filtered to exclude entries with repeated elements (those
from the same position in the input pool)::

def permutations(iterable, r=None):
pool = tuple(iterable)
n = len(pool)
r = n if r is None else r
for indices in product(range(n), repeat=r):
if len(set(indices)) == r:
yield tuple(pool[i] for i in indices)

The number of items returned is ``n! / (n-r)!`` when ``0 <= r <= n``
or zero when ``r > n``.

.. function:: product(*iterables, repeat=1)

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