8000 fix: scalar timestamp assignment (#19843) by DylanDmitri · Pull Request #19973 · pandas-dev/pandas · GitHub
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fix: scalar timestamp assignment (#19843) #19973

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Merged
merged 7 commits into from
Aug 2, 2018
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fix: scalar timestamp assignment (#19843) #19973

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5a9b1b9
fix: scalar timestamp assignment (#19843)
DylanDmitri Mar 2, 2018
601cf54
moved tests
DylanDmitri Mar 2, 2018
33f8651
issue number in tests
DylanDmitri Mar 2, 2018
59069b9
added whatsnew
DylanDmitri Mar 3, 2018
edcb4e2
Merge branch 'master' into PR_TOOL_MERGE_PR_19973
jreback Aug 2, 2018
c48fbe9
update docs
jreback Aug 2, 2018
1b9649c
clean
jreback Aug 2, 2018
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issue number in tests
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@DylanDmitri
DylanDmitri committed Mar 2, 2018
commit 33f865129a9cfc3aa4ecba4b5a5f2b5e531b4178
6 changes: 2 additions & 4 deletions pandas/tests/frame/test_indexing.py
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Expand Up @@ -3045,19 +3045,17 @@ def test_transpose(self):
assert_frame_equal(result, expected)

def test_scalar_assignment(self):
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Reference issue number for both tests.

# issue #19843
df = pd.DataFrame(index=(0, 1, 2))

df['now'] = pd.Timestamp('20130101', tz='UTC')

assert isinstance(df.dtypes[0], DatetimeTZDtype)
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construct the expected frame and use assert_frame_equal

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put this in class TestDataFrameIndexingDatetimeWithTZ(TestData)

name it test_setitem_scalar

parameterize it with both a tz and a tz-aware value.


def test_datetime_index_assignment(self):
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this is a duplicate test.

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you could put it as an additional test in the class as above if you'd like (parametrize as well)

# issue #19843
df = pd.DataFrame(index=(0, 1, 2))

di = pd.DatetimeIndex(
[pd.Timestamp('20130101', tz='UTC')]).repeat(len(df))
df['now'] = di

assert isinstance(df.dtypes[0], DatetimeTZDtype)


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