8000 BUG: TimedeltaIndex raising ValueError when slice indexing (#16637) by jdeschenes · Pull Request #16638 · pandas-dev/pandas · GitHub
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BUG: TimedeltaIndex raising ValueError when slice indexing (#16637) #16638

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Merged
merged 13 commits into from
Jul 6, 2017
Merged

BUG: TimedeltaIndex raising ValueError when slice indexing (#16637) #16638

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6d23625
BUG: TimedeltaIndex raising ValueError when slice indexing (#16637)
Jun 8, 2017
6309877
v0.20.2 is already released
Jun 8, 2017
094d25a
Fixed unit tests.
Jun 8, 2017
4a0b379
This test would fail on 32 bits.
Jun 8, 2017
d842230
Changes based on review comments
Jun 9, 2017
00675c0
* Fixed bug on windows with int32/int64 confusion
Jun 9, 2017
12ecdc4
Final change based on @jreback comments
Jun 9, 2017
dc8cb7a
Using pytest parametrize as per @jreback suggestion.
Jun 9, 2017
358bfca
Unneeded try except.
Jun 12, 2017
186549a
Corrections from @jreback comments
Jul 3, 2017
7df27da
Fixed lint issue
Jul 3, 2017
b38d6ba
Merge branch 'master' into bug_delta_time
TomAugspurger Jul 5, 2017
b5f43a0
Update v0.20.3.txt
TomAugspurger Jul 5, 2017
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Fixed lint issue
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Jean-Mathieu Deschenes committed Jul 4, 2017
commit 7df27da8e6dd4aaffc1bf985d191ffae1365ece3
9 changes: 5 additions & 4 deletions pandas/tests/indexing/test_timedelta.py
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Expand Up @@ -22,10 +22,11 @@ def test_boolean_indexing(self):
dtype='int64')
tm.assert_frame_equal(expected, result)

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just make sure test is near other slicing testsing (may not actually be many).

@pytest.mark.parametrize("indexer, expected",
[(0, [20, 1, 2, 3, 4, 5, 6, 7, 8, 9]),
(slice(4, 8), [0, 1, 2, 3, 20, 20, 20, 20, 8, 9],),
([3, 5], [0, 1, 2, 20, 4, 20, 6, 7, 8, 9])])
@pytest.mark.parametrize(
"indexer, expected",
[(0, [20, 1, 2, 3, 4, 5, 6, 7, 8, 9]),
(slice(4, 8), [0, 1, 2, 3, 20, 20, 20, 20, 8, 9]),
([3, 5], [0, 1, 2, 20, 4, 20, 6, 7, 8, 9])])
def test_list_like_indexing(self, indexer, expected):
# GH 16637
df = pd.DataFrame({'x': range(10)}, dtype="int64")
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