8000 numpy.remainder not working as defined. · Issue #7272 · numpy/numpy · GitHub
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jakehanson opened this issue Feb 18, 2016 · 4 comments
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numpy.remainder not working as defined. #7272

jakehanson opened this issue Feb 18, 2016 · 4 comments

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@jakehanson
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For some reason, numpy.remainder function is not working as defined for the following specific case:

np.remainder(.60,.04) = 0.04

0.60-np.floor(0.60/0.04)*0.04 = 0.00 (Function as defined)

This seems to be the only case for which the definition does not match the function output.
@njsmith
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njsmith commented Feb 18, 2016

What version of numpy?

On Wed, Feb 17, 2016 at 9:32 PM, jakehanson notifications@github.com
wrote:

For some reason, numpy.remainder function is not working as defined for
the following specific case:

np.remainder(.60,.04) = 0.04

0.60-np.floor(0.60/0.04)*0.04 = 0.00 (Function as defined)

This seems to be the only case for which the definition does not match the
function output.

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#7272.

Nathaniel J. Smith -- https://vorpus.org http://vorpus.org

@omegahm
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omegahm commented Feb 18, 2016

I'm not sure what it is, that isn't working:

>>> np.__version__
'1.10.4'
>>> 0.60 % 0.04
0.039999999999999966
>>> np.remainder(0.60, 0.04)
0.039999999999999966

@pv
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pv commented Feb 18, 2016

Probably duplicate of gh-7224

@jakehanson
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Hi Pauli, I beleive you're correct. Ideally i would like the remainder to
return something close to 0 rather than x2 if x1 is divisible by x2, but I
understand how floating point error can cause this. Thank you all for the
responses.
On Feb 18, 2016 7:02 AM, "Pauli Virtanen" notifications@github.com wrote:

Probably duplicate of gh-7224 #7224

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#7272 (comment).

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@pv @omegahm @njsmith @jakehanson
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