Gesalbte

Wikipedia:Babel

en-4This user can contribute with a near-native level of English.

zh-3該用戶能以熟練的中文進行交流。
该用户能以熟练的中文进行交流。

de-2Dieser Benutzer hat fortgeschrittene Deutschkenntnisse.

la-1Hic usor simplici latinitate contribuere potest.

ja-1この利用者は初級の日本語ができます。

ipa-3
əThis user has an advanced understanding of the International Phonetic Alphabet.

This user thinks good grammar is sexy.

USThis user uses American English.

big wordsThis user opposes the use of esoteric, abstruse and recondite ^big words in Wikipedia articles when simple ones will do.

to¦goThis user chooses to sometimes use split infinitives.

byThis user does not use the passive voice.

Thou/YeThis user wants to resurrect the T–V distinction in English.

This user lives in the
United States of America.

DL	This user supports the Left Party of Germany

This user believes that all men are created equal.

This user loves Science.

This user is interested in the belief that the Meaning of life is to Improve Oneself.

This user is a professional chemist.

CommerceThis user is a student of Commerce (Business and Economics).

TV-0This user has no television set.

This user enjoys ballet dancing.

This user is already a citizen of Heaven because he believes Jesus is the only way.

This user is a student of Economics.

QThis user is a rationalist.

This user has a keen interest in physics.

This user is interested in the Byzantine Empire.

This user has been assimilated. Resistance is futile.

This user is interested in the Crusades.

This user enjoys classical music (especially with Violin).

Search user languages

Calculus

$\int _{a}^{b}f(x)\,dx=F(b)-F(a).$

${\begin{aligned}\lim _{m\rightarrow +\infty }P(1+{\frac {r}{m}})^{mt}&=\lim _{m\rightarrow +\infty }P{\frac {{[(m+r)^{mt}]}'}{{(m^{mt})}'}}\\&=\lim _{m\rightarrow +\infty }P{\dfrac {{\dfrac {\operatorname {d} [(m+r)^{m}]^{t}}{\operatorname {d} [(m+r)^{m}]}}\centerdot {\dfrac {\operatorname {d} [(m+r)^{m}]}{\operatorname {d} (m+r)}}\centerdot {\dfrac {\operatorname {d} (m+r)}{\operatorname {d} m}}}{{\dfrac {\operatorname {d} (m^{m})^{t}}{\operatorname {d} (m^{m})}}\centerdot {\dfrac {\operatorname {d} m^{m}}{\operatorname {d} m}}}}\\&=\lim _{m\rightarrow +\infty }P{\frac {t(m+r)^{(t-1)m}\centerdot (m+r)^{m}[1+\ln {(m+r)}]\centerdot (1+r)}{t[m^{(t-1)m}]\centerdot m^{m}(1+\ln m)}}\\&=\lim _{m\rightarrow +\infty }P(1+r)\\&=P(1+r)\end{aligned}}$

See Also

• Gesalbte's Userboxes
• Cool images