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%I A366573 #13 Dec 30 2023 13:04:01
%S A366573 1,1,1,2,1,6,1,6,1,10,1,6,1,210,1,2,3,10,1,42,1,110,3,2,1,546,1,2,1,
%T A366573 30,1,462,1,170,3,2,1,51870,1,2,3,110,1,42,1,46,15,2,1,1326,1,22,3,10,
%U A366573 1,798,1,290,3,2,1,930930,1,2,3,34,5,966,1,2,3,110,1
%N A366573 a(n) = denominator(Bernoulli'(n, x)) / denominator(Bernoulli''(n, x)).
%F A366573 a(n) = A324370(n) / A366168(n).
%p A366573 seq(denom(diff(bernoulli(n, x), x))/denom(diff(diff(bernoulli(n, x), x),x)), n = 0..100);
%o A366573 (PARI) a(n) = lcm(apply(denominator, Vec(deriv(bernpol(n)))))/ lcm(apply(denominator, Vec(deriv(deriv(bernpol(n)))))); \\ _Michel Marcus_, Oct 14 2023
%Y A366573 Cf. A324370/A366168, A366572, A144845/A366168.
%K A366573 nonn
%O A366573 0,4
%A A366573 _Peter Luschny_, Oct 13 2023

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